Simplifying Radical Expressions1. Created by Sal Khan and Monterey Institute for Technology and Education.
Want to join the conversation?
- how do you find all the real fourth roots of numbers?(12 votes)
- Why did the cube root of -1 turn out to be -1 ????(7 votes)
- Well, if you think about it, -1 to the third power is equal to -1.
-1 * -1 * -1two negatives cancel out, times a third is negative:
The answer is *-1*(15 votes)
- None of the videos deal with fractions. How would I go about finding the square root of fractions? Can they not be simplified?(14 votes)
- I think you solve the fractions the same way the ones shown above are solved you just divide the common factors instead of multiplying them.(4 votes)
- Is there a video of0:37where he goes through the rules of how you know what something is divisible by?
It's another part of my swiss cheese math brain I need filled in.(8 votes)
- What Sal is doing at0:37is called prime factorization. There is actually a topic entirely focused on prime factorization. You can find it here: https://www.khanacademy.org/math/arithmetic/factors-multiples/prime_factorization
There is also a topic focused on recognizing divisibility, which will help you to understand what a given number is divisible by. You can find that topic here: https://www.khanacademy.org/math/arithmetic/factors-multiples/divisibility_tests(3 votes)
- I'm trying to do the pythogrean theorem but in the answer block it asks for a simplified radical and i watched this video but it still does not make any sense...
any ideas?(5 votes)
- A radical expression is an expression that includes the root of a number. Am I right in guessing that the answer space for the pythagorean theorem problems includes a regular box and a box under a square root sign? If so, then you simply need to simplify the square root of the answer.
For instance, if you had a right triangle with legs 2 and 4 and hypotenuse c, then you use the pythagorean theorem, which is a^2 + b^2 = c^2.
Add the squares of the legs (a and b in the equation above) to get 2^2 + 4^2 = 4 + 16 = 20.
To get c, you take the square root of a^2 + b^2, so c is equal to sqrt 20.
Because 4 times 5 = 20, you can get sqrt 20 = sqrt (4 x 5)
This simplifies into (sqrt 4) x (sqrt 5) = 2 x (sqrt 5), which would be the answer.
Hope that this helps!(5 votes)
- In the Simplifying Radicals video, u simplyfied the radical by using the following formula:
Problem: simplify the square root of 72
Step 1) the square root of 72 = the square root of 36x2
2) the square root of 36x2 = 36 squared x 2 squared
3) the square root of 36 = 6
Answer: 6 x the square root of 2
In this video u simplified radicals by using a factor tree. Which formula should I use???(6 votes)
- you can use the factor tree or any prime factorization method that you find useful because they all work. using the factor tree is helpful at first because it lais out all the primes and is easy to count when grouping together the primes.(3 votes)
- so a square root is like dividing the number by 2(1 vote)
- No, though there is a connection with square roots and the number 2. Multiplying 2 of the same number (8*8, 2*2, 5*5) results in a square number.
A square root is working backwards. Finding a square root is the same as asking, "What number, when multiplied by itself, equals the number I'm trying to find the square root of?"
I hope that helped.(10 votes)
- at1:46y does he keep adding 7 onto the end ?(3 votes)
We're are asked to find the cube root of negative 343. Or another way to think about it is some number that when I multiply it by itself three times, I'm going to get negative 343. Or another way to view it-- this is the same thing as negative 343 to the 1/3 power. And the best way to do this is to really just try to factor this out. So the first thing that we could do-- so let me just factor negative 343. So the first thing I'd like to do is just factor out the negative 1. So this is the same thing as negative 1 times 343. And let's think about this. Is this divisible by 2? No. Is it divisible by 3? Let's see-- the digits do not add up to a multiple of 3. They add up to 10. So it's not divisible by 3. Not divisible by 4 since it's odd. Not divisible by 5 because it doesn't end with a 5 or a 0. It's not divisible by 6, because it's not divisible by 2 or 3. Is it divisible by 7? Let's check this out. So 7 goes into 343-- 7 goes into 34 four times. 4 times 7 is 28. 34 minus 28 is going to be 6. Bring down the 3. 7 goes into 63 exactly nine times. So then we end up-- so 9 times 7 is 63, no remainder. So this is going to be 7 times 49. And we know that 49 is the same thing as 7 times 7. So how can we rewrite this? This is the same thing as taking the cube root of negative 1 times 7 times 7 times 7, which is the same thing as taking the cube root of negative 1 times the cube root of 7 times 7 times 7. Now, what's the cube root of negative 1? Well, negative 1 times itself three times is negative 1. So this right here is negative 1. You could verify it. Negative 1 times negative 1 times negative 1 is indeed negative 1. This becomes positive 1. Multiply by negative 1 again, you get negative 1. So this is negative 1. And then this over here, the cube root of 7 times 7 times 7-- well, that's just going to be 7. 7 multiplied by itself three times gives us 7 times 7 times 7 or 343. So it's going to be negative 1 times 7, which is the same thing as negative 7. So our answer is negative 7. And we're done.