- Drawing a quadrilateral on the coordinate plane example
- Drawing polygons with coordinates
- Area of a parallelogram on the coordinate plane
- Area and perimeter on the coordinate plane
- Coordinates of a missing vertex
- Example of shapes on a coordinate plane
- Dimensions of a rectangle from coordinates
- Coordinates of rectangle example
- Quadrilateral problems on the coordinate plane
- Quadrilateral problems on the coordinate plane
- Parallelogram on the coordinate plane
- Coordinate plane FAQ
Remember our discussion of the coordinate plane? Sure you do! Let's graph the given coordinates of three of the polygon vertices, and find where the 4th vertex is. Created by Sal Khan.
Want to join the conversation?
- what would a line with a negative length look like?(13 votes)
- Well a line will always be positive because it's straight with no curves but you can say that the points can be negative so in conclusion it'll just look like any other line(18 votes)
- I dont get1:25. can someone help?(9 votes)
- This is just instructions from the math problem saying that Sal has to make both lines the same length. I hope that's what you were asking for, and if it isn't, please be more specific.(16 votes)
- I don't get it please help.(14 votes)
- if anyone has a problem remembering horizontal and vertical, here is a simple trick. Horizontal comes from the line in the horizon of the sun, sea, ocean, etc. I hope this helped :)(11 votes)
- I've heard that a polygon cannot have curved edges or incomplete sides, so would a circle not be considered a polygon? I mean it is a shape, and all shapes are polygons, right?(7 votes)
- Not all shapes are polygons, and circles have curved sides so they are not polygons.(8 votes)
- If we use the distance formula to solve for this, without knowing that it has to be a parallelogram, than we can get many points that make a polygon ABCD but the polygon is not a parallelogram! Then why does it have to be a parallelogram?(7 votes)
- This problem does not say to use the distance formula. Yes, I know this sounds like the problem is some dictator, but, while we're doing it, it is a dictator of sorts.(7 votes)
- why not just count the units?(6 votes)
- You definitely can just count the units. However, if you're dealing with units that are farther apart....... maybe with distances of 100 or more in between, then counting would become a long and tedious process.
You could also just take the absolute value of the x-coordinates since the y-coordinates are the same to find the distance in between.
Ex. | -1.5 - 4.5 | = | -6 | = 6(6 votes)
- Does anybody else have a problem in using "Drawing polygons with coordinates" For me it is not might user friend. I know the answer but cannot get the hang of plotting it on screen.(7 votes)
- Yes I do sometimes, but if you keep practicing plotting different ones out, you start to get better at drawing them out correctly. Hopefully that helps!(3 votes)
- how big is the biggest coordinate plane (in Numbers) in the world?(5 votes)
- The biggest coordinate plane in the world is infinitely long in EVERY direction. On a lot of apps you can keep zooming out forever.(5 votes)
- i am soooo lost. like when this site gives me the questions, and i line up all the stuff like you are, id have to throw in a random line thats not being questioned... and idk if im getting thrown off track because like around3:38ish in the video your like counting the squares between the points, so then im thinking i have to do that to get the answer, you know? idk if any of this makes sense but im just sooo confused. and im not trying to be mean because you are helping me a lot. but im just confused, like why does this seem like such a simple thing that i should easily know but theres this long process, you know?(5 votes)
You are graphing polygon ABCD in the coordinate plane. The length of segment AB must be the same as the length of segment DC, and both segments are horizontal segments. The following are three of the vertices of the polygon. Vertex A is at the point 1, 1. It puts us right over there. That is the vertex A. Vertex C is at the point 4.5 comma 4, so 4.5 along the horizontal axis comma 4. So we go all the way up to 4. That right over there is point C. Point D is at negative 1.5 comma 4, so negative 1.5 along the horizontal or the x-axis, we could say, negative 1.5 comma 4, so 4 along the vertical or the y-axis. We go right over there. That's close enough. So that, of course, is our y-axis. This is point D. And we need to figure out what are the coordinates of point B if B must be in quadrant I. And they tell us that the distance from A to B must be the same as the length of segment D to C in both our horizontals. So let's draw what we know to draw. So DC, segment DC is this segment right over here. And we see it's horizontal. Both of the vertical coordinates are 4 at both vertex D and vertex C. So both of the vertical coordinates are 4. Now what is the length of this? Because we're going to have to construct another segment that has the same length. Well, along the horizontal direction, we went from negative 1.5 to 4.5. So how far did we go? Well, to go from negative 1.5 to 0, you go 1.5, and then you have to go another 4.5. So this is going to be 4.5 plus 1.5, which is equal to 4 plus 1 is 5, 0.5 plus 0.5 is 1, so 5 plus 1 is 6. So this distance right over here is 6 of our units. Actually, let me put the coordinates in here, just so it becomes a little bit clearer. Let me do that in something easier to see. This right over here is the point 4.5, 4, and this right over here is the point negative 1.5, 4. Another way of thinking about this distance is you could take the end point-- and we're really thinking about the distance just along its horizontal line, so the y-value does not change. It doesn't change in the vertical direction, only the horizontal. So you really want to say, if you start at negative 1.5 and you get to 4.5, how far have you gone? So you can just take your end point, your end value, your end horizontal value or your end x-value, and from that, you can subtract your starting x-value. So you subtract negative 1.5. And this, of course, is equal to 4.5 plus positive 1.5, which, once again, is equal to 6. Fair enough. And let me draw some of the rest of the polygon, just so that we see it is indeed a polygon. We have this side right over here. It looks like it's going to be a parallelogram. We have this side right over here. And we have to replace point B. Now, point B is going to be someplace out here. It's going to have the same vertical value or the same y-value as point A. So its y-coordinate is going to be 1. So point B is going to be out here someplace. Let me do this in a new color. I haven't used this orange yet. Actually, I have used the orange yet. I haven't use the yellow. No, I've used the yellow. Let's see. I haven't used this green. Point B is going to be someplace out here. We already know what its y-coordinate is. It's a horizontal line, so it's going to have to have the same exact y-coordinate as point A. Point A's y-coordinate was 1, so this is going to have to have a y-coordinate of 1. Now the big question is, what is its x-coordinate going to be? Let me do that in a different color. It's going to have to be whatever A's x-coordinate was. We see that A's x-coordinate was 1. And it's going to have to be that plus 6, because we're going to move the same distance in the horizontal direction. This thing has to be 6. So if we start at 1, we add 6, we get to 7. So what are the coordinates of point B, especially if point B must be in quadrant I? And notice we are definitely in quadrant I. This is quadrant I, this is quadrant II, this is quadrant III, and this is quadrant IV. The coordinate for point B is 7 comma 1.