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### Course: 5th grade > Unit 5

Lesson 4: Multi-digit division- Long division with remainders: 2292÷4
- Long division with remainders: 3771÷8
- Introduction to dividing by 2-digits
- Basic multi-digit division
- Dividing by 2-digits: 9815÷65
- Dividing by 2-digits: 7182÷42
- Dividing by a 2-digits: 4781÷32
- Division by 2-digits
- Multi-digit multiplication and division: FAQ

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# Multi-digit multiplication and division: FAQ

Frequently asked questions about multi-digit multiplication and division.

## Why do we need to learn multi-digit multiplication and division?

There are many situations in the real world where we need to multiply or divide numbers that are larger than just one digit. For example, if we want to calculate the cost of $17$ items that each cost $12$ , we'll need to multiply $17\times 12$ .

## How can we estimate multi-digit multiplication and division problems?

One way to estimate is to round each number to the nearest ten, hundred, or thousand (depending on the size of the numbers) and then multiply the rounded numbers together. For example, to estimate $238\times 24$ , we could round each number to the nearest ten: $240\times 20=\mathrm{4,800}$ .

For division, we can estimate the dividend and divisor to the nearest ten, hundred, or thousand (depending on the size of the numbers) and then divide the rounded numbers. For example, to estimate $314\xf727$ , we could round each number to the nearest ten: $310\xf730=10$ .

Try it yourself with these exercises:

## Why do we need to learn how to factor out multiples of ten when multiplying and dividing?

Working with multiples of ten is often easier because of the way our base-ten number system is structured. So, by factoring out tens, we may be able to break down a difficult multiplication or division problem into a simpler one.

Try it yourself with these exercises:

## What is the standard algorithm for multiplication and how do we use it?

The standard algorithm for multiplication involves breaking one of the numbers down into its place values, multiplying each place value by the other number, and then adding the results together.

For example, we can use the standard algorithm to multiply $83\times 9$ .

First, we multiply ${9}\times {3}$ .

Next, we multiply $({9}\times {80})+{20}$ .

Try it yourself with these exercises:

## What are remainders and how do they relate to division?

The remainder is the amount left over when you divide one number by another and the division doesn't come out evenly. For example, if we divide $10$ by $2$ , we get a whole number result of $5$ , with no "leftovers." But if we divide $10$ by $3$ , you get a result of $3$ with a remainder of $1$ .

Try it yourself with these exercises:

## Want to join the conversation?

- Currently a HS freshman with ADHD relearning math from the absolute basics, just cleared this unit. I'm proud of myself :)(63 votes)
- omg this is hard for me 2 learn i really need help(17 votes)
- try your best! think positive you guys can do it!💖(16 votes)

- this is HARD for me(5 votes)
- not so hard(4 votes)

- Ask a question....(6 votes)
- the answer is 10(3 votes)

- 240 is the correct answer(5 votes)

- Is it normal to not watch most of these videos?(3 votes)
- id say you don't watch 'em first try with the way u understand then if youre wrong then watch 'em-_-(3 votes)

- oof its not ez(3 votes)
- I have the same feeling here to it is so hard 😡 you need a big brain for this (2 votes)

- How do you multiply 2 digits? Kinda figured it out but still struglin.(2 votes)
- Ok, i hope this helps

23

x 9

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u first multiply 9x3, which is 27. u then carry over 2 to the tens place and put 7 below the ones. then u do 9x2, plus any carry-overs, which, in this case is a 2. all of that is 20, and u put it under the tens place. the final thing should look like this:

29

x 3

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207(3 votes)

- kahn academy is fun and it teaches us a lot(2 votes)