AP®︎/College Calculus AB
When we're provided with an appropriate table of values of a function, we can use it to estimate the function's limit at a certain point.
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- My gut says that there must be a function f(x) that gives us this exact table but has the value of 6.37 as its limit. We can't know for sure if the function suddenly (but continuously!) shoots up to 6.37 and back down again or not. So why exactly is it a reasonable estimate to say it doesn't?(30 votes)
- From the author:I agree with you. We definitely don't know for sure just with a table (which only samples the function). But in this example, we need to pick the most reasonable estimate, and, in general, it is usually most reasonable to assume that something wacky doesn't happen unless it is explicitly pointed out.(55 votes)
- Can someone explain why 3.68 is a better estimate than 4 for the limit?(8 votes)
- Because 3.68 is more accurate than 4.
3.68 probably isn't the exact limit either, but given the table it is our best bet.(14 votes)
- I thought at the limit there would be no value, it would be undefinied. So when the limit goes to 5, and g(x) is 6.37 in this problem, doesn't that mean the limit doesn't exist?(2 votes)
- The question reads: What is a reasonable estimate for the limit of 𝑔(𝑥) as 𝑥 approaches 5?
So, loosely speaking, we are looking for some value 𝐿 (the limit), such that when 𝑥 gets very, very close to 5 (without actually being equal to 5), then 𝑔(𝑥) gets very, very close to 𝐿.
Looking at the table we see that as 𝑥 goes from 4 to 4.999, 𝑔(𝑥) increases and gets closer and closer to 3.68 .
And, as 𝑥 goes from 6 to 5.001, 𝑔(𝑥) decreases and gets closer and closer to 3.68 .
Thereby it is reasonable to assume that the limit of 𝑔(𝑥) as 𝑥 approaches 5 does exist, and that it's value is 3.68 .(5 votes)
- Well in n the graph plotted in most of the questions,test,examples has two different points marked 1) A closed (solid) dot means the endpoint is included in the curve and 2)an open dot means it isn't ...My doubt is if it is the open dot then how does the answer here turn out to 3.68(2 votes)
- Since in question, it is asked "What g(x) approaching as x approaches 5?" When we check for limit from left hand side (i.e., values less than 5) for x = 4.999 (which is very close to 5) we get g(x) = 3.68. Similarly, if we check for limit from right hand side (values that greater than 5), for x = 5.001 we get g(x) = 3.68. So, limit from RHS and LHS are equal, therefore limit for g(x) as x approaches 5 is 3.68.
It does matter if g(x) is different at x = 5 or in your words there is open dot (or for sake of discussion, lets say undefined) because in question we not asked for value of g(x) at x=5 but what we g(x) is approaching as x approaches 5.(5 votes)
- Do we disregard the solid point on the graph?(2 votes)
- It may have saved a lot of confusion if it had been stated in the beginning that the function was not continuous over the interval [4,6].(3 votes)
- How about the fact that both points are approaching the same value? Shouldn't that make it automatically undefined?(2 votes)
- If the two directions approach the same value then it is explicitly NOT undefined, it is that value. The one exception is when both directions approach infinity, because infinity is not a value.
You want both directions to approach the same value though(1 vote)
- what about a graph like x=5, that is a straight line parallel to y axis. what's the limit as x approaches 5?(1 vote)
- Are there known precedures , defined to try and build an equation which has been formed using a data table for a f(n) ??(2 votes)
- There are infinitely many functions that pass through any given set of points, so no.
However, if you're given a set of n-many points, no two with the same x-coordinate, then there is a unique n+1-degree polynomial that passes through all of them.(1 vote)
- Why we are adding the word "approximately" to the limit when we find the value of that? like "the approximate value of the limit of this function is 3.68".
So these values are not accurate/exact values of that limit?
If yes, how?(1 vote)
- The issue is that you only have 4.999, but the limit can get closer to that, what would 4.9999 or 4.99999 be? The assumption from the given values is that there will not be a big jump past 3.68, but there might be a small increment such as 3.681 that would make it only an approximate value. Hope this makes sense.(2 votes)
- [Teacher] The function g is defined over the real numbers. This table gives select values of g. What is a reasonable estimate for the limit is x approaches five of g of x? So pause this video, look at this table. It gives us the x values as we approach five from values less than five and as we approach five from values greater than five it even tells us what g of x is at x equals five. And so, given that, what is a reasonable estimate for this limit? Alright now let's work through this together. So let's think about what g of x seems to be approaching as x approaches five from values less than five. Let's see at four is it 3.37, 4.9? It's a little higher. Is it 3.5, 4.99? Is it 3.66? 4.999; so very close to five. We're only a thousandth away, we're at 3.68. But then at five all of a sudden it looks like we're kind of jumping to 6.37. And once again, I'm making an inference here. I don't, these are just sample points of this function, we don't know exactly what the function is. But then if we approach five from values greater than five. At six we're at 3.97; at 5.1 we're at 3.84. 5.01; 3.7; 5.001; we're at 3.68. So a thousandth below five and a thousandth above five we're at 3.68, but then at five all of sudden we're at 6.37. So my most reasonable estimate would be, well it look like we're approaching 3.68. When we're approaching from values less than five. And we're approaching 3.68 from values as we approach five from values greater than five. It doesn't matter that the value of five is 6.37. The limit would be 3.68 or a reasonable estimate for the limit would be 3.68. And this is probably the most tempting distractor here because if you were to just substitute five; what is g of five? It tells us 6.37, but the limit does not have to be what the actual function equals at that point. Let me draw what this might look like. So an example of this, so if this is five right over here, At the point five the value of my function is 6.37, so let's say that this right over here is 6.37, so that's the value of my function right over there. So 6.37, but as we approach five, so that's four, actually let me spread out a little bit. This obviously is not drawing to scale. But as we approach five, so if this, that's 6.37; then at four, 3.37 is about here and it looks like it's approaching 3.68. So 3.68, actually let me draw that. So 3.68 is gonna be roughly that. 3.68 is gonna be roughly that. So the graph, the graph might look something like this. We can infer it looks like it's doing something like this. Where it's approaching 3.68 from values less than five and values greater than five, but right at five, our value is 6.37. I don't know for sure if this is what the graph look like once again, we're just getting some sample points. But this would be a reasonable inference. And so you can see, our limit. We are approaching 3.68, even though the value of the function is something different.