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## The fundamental theorem of calculus and accumulation functions

# Finding derivative with fundamental theorem of calculus: chain rule

AP.CALC:

FUN‑5 (EU)

, FUN‑5.A (LO)

, FUN‑5.A.1 (EK)

, FUN‑5.A.2 (EK)

## Video transcript

- [Instructor] Let's say
that we have the function capital F of x, which we're going to define
as the definite integral from one to sine of x, so that's an interesting
upper bound right over there, of two t minus one, and of course, dt, and what we are curious about is trying to figure out
what is F prime of x going to be equal to? So pause this video and see
if you can figure that out. All right. So some of you might have
been a little bit challenged by this notion of hey, instead of an x on this upper bound, I now have a sine of x. If it was just an x, I could have used the
fundamental theorem of calculus. Just to review that, if I had a function,
let me call it h of x, if I have h of x that was
defined as the definite integral from one to x of two t minus one dt, we know from the fundamental
theorem of calculus that h prime of x would be simply this inner function with the t replaced by the x. It would just be two x minus
one, pretty straightforward. But this one isn't quite
as straightforward. Instead of having an x up here, our upper bound is a sine of x. So one way to think about it
is if we were to define g of x as being equal to sine of x, equal to sine of x, our capital F of x can be
expressed as capital F of x is the same thing as h of, h of, instead of an x, everywhere we see an x, we're replacing it with a sine of x, so it's h of g of x, g of x. You can see the g of x right over there. So you replace x with g of x for where, in this expression, you get h of g of x and that is capital F of x. Now why am I doing all of that? Well, this might start making you think about the chain rule. Because if this is true, then that means that capital F prime of x is going to be equal to h prime of g of x, h prime of g of x times g prime of x. And so what would that be? Well, we already know
what h prime of x is, so I'll need to do this in another color. This part right over
here is going to be equal to everywhere we see an x here, we'll replace with a g of x, so it's going to be two, two times sine of x. Two sine of x, and then minus one, minus one. This is this right over here, and then what's g prime of x? G prime of x, well g prime of x is just, of course, the derivative of sine
of x is cosine of x, is cosine of x. So this part right over here is going to be cosine of x. And we could keep going. We could try to, we could try to simplify this a little bit or rewrite it in different ways, but there you have it.

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