AP®︎/College Calculus AB
Definite integrals represent the area under the curve of a function and above the 𝘹-axis. Learn about the notation we use to write them and see some introductory examples.
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- what is dx suppose to represent in the notation?(22 votes)
- Integration basically means summing up the area of infinitesimally thin rectangles under a function in a given interval [a, b]. The infinitesimally small width of the rectangles is denoted dx. Hope this helps!(48 votes)
- I think there's something wrong with the video. It says7:53minutes but it ends at2:24for me.(24 votes)
- Hi Selim, this appears to be a issue on Khan Academy end. It seems like all the necessary content is covered in the video however.
I would suggest you move on to next part.(8 votes)
- Is there a way can do this process without graph?(13 votes)
- At1:36in the video, Sal describes the mathematical notation for the definite integral of f(x) evaluated from a to b. There is no need for a graph at all, simply find the antiderivative of f(x), then evaluate that antiderivative at b, and subtract the antiderivative evaluated at a.(22 votes)
- is this video supposed to be longer than2:27? it feels like he got cut off. I didnt really learn anything from this because it feels like he didnt finish. I also see other people in the comments saying this but with no response.(13 votes)
- Nope! This is how long this specific video is supposed to be. It continues later, but that's when you're supposed to learn more.(3 votes)
- Hi! I am a bit confused with what dx means in the video ... does anyone know?
- dx,is always "a small change in x" it amounts to the limit of x as x goes to 0. or whatever is next tot he d(4 votes)
- Hey hey! So there's a second coordinate plane in this video, but no graph or function. I might realize there's a continuation of this video somewhere, but wanted to catch it early in case I forget. Is there supposed to be more to this?
Thanks a bunch!(6 votes)
- what is the difference between exact area and definite integral?(3 votes)
- The definite integral gives you a SIGNED area, meaning that areas above the x-axis are positive and areas below the x-axis are negative. That is why if you integrate y=sin(x) from 0 to 2Pi, the answer is 0. The area from 0 to Pi is positive and the area from Pi to 2Pi is negative -- they cancel each other out.
If you want to use integration to find a geometric (or exact, as you called it) area, you have to make all of the negative areas positive. One way to do this is with absolute values or just ignoring negative areas. For example, integrating y=|sin(x)| is not fun, so you normally break that into two integrals (0 to Pi and Pi to 2Pi) and ignore negative signs in the answers.(6 votes)
- Where is the video for finding the exact area using Riemann Sums?(2 votes)
- (One little clarification: This is written assuming you already know what Riemann Sums are. If you don't, you can go check out the videos on that.)
It's nowhere, because there's no real way to do that. Riemann Sums are more of a way to get a sense of how much area is under the curve. We can talk about approximating with Riemann Sums, but actually evaluating them when the lines are infinitesimally small is a whole different story. There's a more precise (and most of the time easier) method called the Fundamental Theorem of Calculus that can tell you the exact answer. You can learn about that a bit later in this course. If using that doesn't work, we have computers that can approximate the area with Riemann Sums a lot more precisely than a person can, however, the answer will never be exact.
I'm a student, just like you, so I hope I know what I'm talking about, and that this response made any sense.(6 votes)
- Hello, I don't understand what is interesting about the area under the curve and between "a" and "b".(1 vote)
- well, u can use it for more complex things. like later on u can find the volume of , say,a washer inside a cylinder by finding the area under the curves and all...(5 votes)
- Can you combine 25pi/2 -6?(2 votes)
- [Instructor] What we're gonna do in this video is introduce ourselves to the notion of a definite integral and with indefinite integrals and derivatives this is really one of the pillars of calculus and as we'll see, they're all related and we'll see that more and more in future videos and we'll also get a better appreciation for even where the notation of a definite integral comes from. So, let me draw some functions here and we're actually gonna start thinking about areas under curves. So, let me draw a coordinate axes here, so that's my Y axis, this is my X axis, actually I'm gonna do two cases. So, this is my Y axis, this is my X axis and let's say I have some function here, so this F of X right over there and let's say that this is X equals A and let me draw a line going straight up like that and let's say that this is X equals B, just like that and what we want to do is concern ourselves with the area under the graph, under the graph of Y is equal to F of X and above the X axis and between these two bounds, between X equals A and X equals B, so this area right over here and you can already get an appreciation. We're not used to finding areas where one of the boundaries or as we'll see in the future, many of the boundaries could actually be curves but that's one of the powers of the definite integral and one of the powers of integral calculus. And so, the notation for this area right over here would be the definite integral and so, we're gonna have our lower bound at X equals A, so we'll write it there, we'll have our upper bound at X equals B, right over there. We're taking the area under the curve of F of X, F of X and then DX. Now, in the future we're going to, especially once we start looking at Riemann sums, we'll get a better understanding of where this notation comes from. This actually comes from Leibniz, one of the founders of calculus. This is known as the summa symbol but for the sake of this video you just need to know what this represents. This right over here, this represents the area under F of X between X equals A and X equals B. So, this value and this expression should be the same