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Current time:0:00Total duration:11:05

AP.CALC:

CHA‑2 (EU)

, CHA‑2.B (LO)

, CHA‑2.B.2 (EK)

, CHA‑2.B.3 (EK)

, CHA‑2.B.4 (EK)

In the last video, we found the
slope at a particular point of the curve y is equal
to x squared. But let's see if we can
generalize this and come up with a formula that finds us
the slope at any point of the curve y is equal to x squared. So let me redraw
my function here. It never hurts to
have a nice drawing. So that is my y-axis. That is my x-axis right there. My x-axis. Let me draw my curve. It looks something like that. You've seen that
multiple times. This is y is equal
to x squared. So let's be very
general right now. Remember, if we want to find--
let me just write the definition of our derivative. So if we have some point right
here-- let's call that x. So we want to be very general. We want to find the
slope at the point x. We want to find a function
where you give me an x and I'll tell you the
slope at that point. We're going to call
that f prime of x. That's going to be the
derivative of f of x. But all it does is, look, f of
x, you give-- it's a function that you give it an x, and it
tells you the value of that. And we draw the curve here. With f of x, you give that same
x but it's not going to tell you the value of the curve. It's not going to say,
oh, this is your f of x. It's going to give you the
value of the slope of the curve at that point. So f of x, if you put it into
that function, it should tell you, oh, the slope at that
point, is equal to-- you know, if you put 3 there, you'll say,
oh, the slope there is equal to 6. We saw that in the
last example. So that's what we want to do. And we saw on the last-- I
think it was 2-- videos ago, that we defined f prime of x
to be equal to-- just the-- well, I'll write it this way. It's the slope of the secant
line between x and some point that's a little
bit further away from x. So the slope of the secant
line is change in y. So it's the y value of the
point that's a little bit further away from x. So f of x plus h minus
the y value at x, right? Because this is right here. This is f of x. So minus f of x. All of that over
the change in x. So if this is x plus h
here, the change in x is x plus h minus x. Or this distance right
here is just h. The change in x is going
to be equal to h. So that's just slope of
the secant line, between any 2 points like that. And we said, hey, we could find
the slope of the tangent line if we just take the limit of
this as it approaches-- as h approaches 0. And then we'll be finding the
slope of the tangent line. Now let's apply this idea to
a particular function, f of x is equal to x squared. Or y is equal to x squared. So here, we could have the
point-- we could consider this to be the point x-- x squared. So f of x is just
equal to x squared. And then this would be the
point-- let me do it in a more vibrant color. This is the point x plus h--
that's this point right here. It's a little bit further down. And then x plus h squared. And you know, in the
last video, we did this for a particular x. We did it for 3. But now I want a
general formula. You give me any x and I won't
have to do what I did in the last video for any
particular number. I'll have a general function. You give me 7, I'll tell you
what the slope is at 7. You give me negative 3, I'll
tell you what the slope is at negative 3. You give me 100,000,
I'll tell you what the slope is at 100,000. So let's apply it here. So we want to find the change
in y over the change in x. So first of all, the change
in y is this guy's y value, which is x plus h squared. That's this guy's y
value right here. That's this right here. That's x plus h squared. I just took x plus h,
evaluated, I squared it, and that's its point on the curve. So it's x plus h squared. So that's there right there. And then what's this value? f of x right here is equal to--
I know it's getting messy-- is equal to x squared. If you take your x, you
evaluate the function at that point, you're
going to get x squared. So it's equal to
minus x squared. This is your change in y. That's this distance
right there. And just to relate it to our
definition of a derivative, this blue thing right here is
equivalent to this thing right here. We just evaluated our function. Our function is f of x
is equal to x squared. We just evaluated when x
is equal to x plus h. So if you have to square
it, if I put an a there, it'd be a squared. If I put an apple there,
it'd be apple squared. If I put an x plus h in
there, it's going to be x plus h squared. So this is that thing. And then, this thing right here
is just the function evaluated at the point in question. Right there. So this is our change in y. And let's divide that
by our change in x. Our change in x-- if this is x
plus h and this is just x, our change in x is just
going to be h. So that's where we
get that term from. So this is just a slope
between these 2 points. This is just a slope
between those two points. But, of course, we want to
find-- the limit at this point gets closer and closer to this
point, and this point gets closer and closer
to that point. So this becomes a tangent line. So we're going to take the
limit as h approaches 0, and this is our f prime of x. And this is the exact same
definition of this, instead of being general and saying,
for any function, we know what the function was. It was f of x is
equal to x squared. So we actually applied it. Instead of f of x,
we wrote x squared. Instead of f of x plus h,
we wrote x plus h squared. So let's see if we can
evaluate this limit. So this is going to be equal
to the limit as h approaches 0 to square this out. I'll do it in the same color. That's x squared plus 2xh plus
h squared, and then we have this minus x squared over here. I just multiplied this
guy out over here. And then all of that
is divided by h. Now let's see if we can
simplify this a little bit. Well, you immediately see you
have an x squared and you have a minus x squared,
so those cancel out. And then we can divide
the numerator and the denominator by h. So this simplifies to-- so we
get f prime of x is equal to-- if we divide the numerator and
the denominator by h-- we get 2x plus h. I'm sorry, I forgot my limit. It equals the limit. Very important. Limit as h approaches 0 of
divide everything by h, and you get 2x plus h squared
divided by h is h. And if you remember the last
video, when we did it with a particular x, we said x is
equal to 3, we got 6 plus delta x here. Or 6 plus h here, so
it's very similar. So if you take the limited h
approaches 0 here, that's just going to disappear. So this is just going
to be equal to 2x. So we just figured out that if
f of x-- this is a big result. This is exciting! That if f of x is equal
to x squared, f prime of x is equal to 2x. That's what we
just figured out. And I wanted to make
sure you understand how to interpret this. f of x, if you give me a value,
is going to tell you the value of the function at that point. At prime of x it's
going to tell you the slope at that point. Let me draw that. Because this is a
key realization. And you might, you know, it's
kind of maybe initially unintuitive to think of a
function that gives us the slope, at any point,
of another function. So it looks like this. Let me draw a little
neater than that. Ah, it's still not that neat. That's satisfactory. Let me just draw it in
the positive coordinate. Well, I'll just draw the
whole-- the curve looks something like that. Now this is the
curve of f of x. This is the curve of f of
x is equal to x squared. Just like that. So if you give me a point. You give me the point 7. You apply, you put it in
here, you square it. And it is mapped
to the number 49. So you get the number
49 right there. This is the number 7, 49. You're used to dealing with
functions right there. But what is f prime of 7? f prime of 7. You say, 2 times 7
is equal to 14. What is this 14 number here? What is this thing? Well, this is the slope
of the tangent line at x is equal to 7. So if I were to take that point
and draw a tangent line-- a point that just grazes our
curve-- if I were to just draw a tangent line. That wasn't tangent
enough for me. So that's my tangent
line right there. You get the idea. The slope of this guy-- you do
your change in y over your change in x-- is going
to be equal to 14. The slope of the curve
at y is equal to 7-- is a pretty steep curve. If you wanted to find the
slope, let's say that this is y-- let's say it's
x is equal to 2. I said at x is equal to
7, the slope is 14. At x is equal to 2,
what is the slope? Well, you figure out f prime of
2, which is equal to 2 times 2, which is equal to 4. So the slope here is 4. You could say m is equal
to 4. m for slope. What is f prime of 0? f prime. We know that f of
0 is 0, right? 0 squared is 0. But what is f prime of 0? Well, 2 times 0 is 0. That's also equal to 0. But what does that mean? What's the interpretation? It means the slope of
the tangent line is 0. So a 0 sloped line
looks like this. Looks just like a
horizontal line. And that looks about right. A horizontal line would
be tangent to the curve at y equals 0. Let's try another one. Let's try the point minus 1. So let's say we're right
there. x is equal to minus 1. So f of minus 1, you
just square it. Because we're dealing
with x squared. So it's equal to 1. That's that point right there. What is f prime of minus 1? f prime of minus 1
is 2 times minus 1. 2 times minus is minus 2. What does that mean? It means that the slope of the
tangent line at x is equal to 1, to this curve, to the
function, is minus 2. So if I were to draw the
tangent line here-- the tangent line looks like that-- and
look, it is a downward sloping line. And it makes sense. The slope here is
equal to minus 2.

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