If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains ***.kastatic.org** and ***.kasandbox.org** are unblocked.

Main content

Current time:0:00Total duration:5:36

AP.CALC:

FUN‑4 (EU)

, FUN‑4.A (LO)

, FUN‑4.A.10 (EK)

, FUN‑4.A.11 (EK)

- [Instructor] We have the
graphs of three functions here, and what we know is that one
of them is the function f, another is the first derivative of f, and then the third is the
second derivative of f. And our goal is to figure
out which function is which. Which one is f, which
is the first derivative, and which is the second? Like always, pause this video and see if you can work through it on your own before we do it together. All right, now let's do this together. The way I'm going to tackle
it is I'm gonna try to sketch what we can about the derivatives
of each of these graphs, or the functions
represented by these graphs. So in this first graph
here in this orange color, we can see that the slope
is quite positive here, but then it becomes less
and less and less positive, up until this point where the
slope is going to be zero, and then it becomes more and more and more and more negative. So the derivative of this
curve right over here, or the function represented by this curve is gonna start off reasonably
positive right over there. At this point, the derivative
is gonna cross zero, 'cause our derivative is zero there, slope of the tangent line. And then it's gonna get
more and more negative, at least over the interval that we see. So it might look, I don't
know, something like this. I don't know if it's a line or not. It might be some type of a curve. It would definitely have a
trend something like that. Now, we could immediately tell that this blue graph is not the derivative of this orange graph. Its trend is opposite. Over that interval, it's going from being
negative to positive, as opposed to going from
positive to negative. So we can rule out the blue graph as being the derivative
of the orange graph. But what about this magenta graph? It does look like it has the right trend. In fact, it intersects the
x-axis at the right place right over there. And at least over this interval, it seems it's positive from here to here. So it's positive. This graph is positive when the slope of the tangent
line here is positive. And this graph is negative when the slope of the tangent
line here is negative. Now, one thing that might
be causing some unease to immediately say that this last graph is the derivative of the first one is we're not used to situations where the derivative
has more extreme points, more minima and maxima
than the original function. But in this case, it could just be 'cause we don't see the
entire original function. So, for example, if this last
graph is indeed the derivative of this first graph, then what we see is our
derivative is negative right over here, but then right around here it
starts becoming less negative. So if that point corresponds
to roughly right over there, then over here our slope
will become less and less and less negative, and then at this point our
slope would become zero, which would be right around there. So for example, our graph
might look something like this, we just didn't see it. It fell off of the part of the graph that we actually showed. So I would actually say that this is a good candidate for being, the third function is a good candidate for being the derivative
of the first function. So maybe we could say that this is f and that this is f prime. Now, let's look at the second graph. What would its derivative look like? So over here our slope is quite negative, and it becomes less and
less and less negative until we go right over here
where our slope is zero. So our derivative would
intersect the x-axis right over there. It would start out negative, and it would become less
and less and less negative. And at this point it crosses the x-axis and it becomes more and more positive. So we see here our derivative becomes more and more positive. But then right around here it seems like it's getting less positive again. So it might look something like this where over here it's
becoming less positive again, less positive, less
positive, less positive. Right over here, our
derivative would be zero. Our derivative would
intersect the x-axis there. And then it just looks like it is, the slope is getting more
and more and more negative, so our derivative is gonna get more and more and more negative. Well, what I very
roughly just sketched out looks an awful lot like the
brown graph right over here. So this brown graph does indeed look like the derivative of this blue graph. So what I would say is
that this is actually f, and then this would be f prime. And then if this is f prime, the derivative of that is
going to be f prime prime. So that looks good. I would actually go with this. And if you wanted, just for safe measure, you could try to sketch out what the derivative of
this graph would be. Actually, let's just do that. So over here, the derivative of this, so right now we have a positive slope of our tangent line is getting
less and less positive. It hits zero right over there. So the derivative might
look something like this over the interval. Now, the slope of the
tangent line is getting more and more and more and more negative, right until about that point. So it's getting more and
more and more negative until about that point. And now it looks like
it's getting less and less and less and less negative, all the way until the derivative
goes back to being zero. And then it looks like
it's getting more and more and more and more positive. So the derivative of
this magenta curve looks like an upward opening U. And we don't see that over here, so we could feel good that its derivative
actually isn't depicted. So I feel calling the middle graph f, calling the left graph f prime, and calling the right graph
the second derivative.

AP® is a registered trademark of the College Board, which has not reviewed this resource.