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### Course: AP®︎/College Calculus AB > Unit 5

Lesson 1: Using the mean value theorem- Mean value theorem
- Mean value theorem example: polynomial
- Mean value theorem example: square root function
- Using the mean value theorem
- Justification with the mean value theorem: table
- Justification with the mean value theorem: equation
- Establishing differentiability for MVT
- Justification with the mean value theorem
- Mean value theorem application
- Mean value theorem review

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# Mean value theorem application

Even if a cop never spots you while you are speeding, he can still infer when you must have been speeding... Created by Sal Khan.

## Want to join the conversation?

- So does that mean that if I were to speed, then stop my car and wait a while. (Theoretically ) would I evade the law?(74 votes)
- In a way, yes, the computer/camera system uses a distance and a time. By stopping your car somewhere, you are increasing the time between point A and point B. Therefore lowering your average speed, in the eyes in the computer. Although, in reality, highway patrol would probably ticket you for speeding (via radar), but that's a whole other topic.(71 votes)

- I still don't really see the full purpose of the mean value theorem here because if the speed limit is 55 MILES PER HOUR and the distance between the two points is 80 miles, then wouldn't it be kind of obvious that the person must have exceeded the speed limit if they went from one point to the other in just an hour?(42 votes)
- Exactly. That is the simplified version of what the mean value theorem is exactly telling you.

Is it obvious? Sure.

But it can be mathematically proved using the mean value theorem, and that's why it is of importance.(64 votes)

- I think there is a simpler way to tackle this problem.

Can not we say without bringing the notion of mean value theorem in mind that if the average speed is 80 mph, the maximum speed that the driver achieved during the journey is equal to or more than 80 mph. Therefore the maximum allowed speed limit (55 mph) must have been crossed. And this does not require the knowledge of nature of the function (continuity and differentiability).

Is there mean value theorem underlying in inferring the problem this way?

If so then we are using mean value theorem without knowing it !!(24 votes)- Yes, you are right in all your affirmations. Knowing that the average speed was 80mph is enough to know that at some point the speed was equal to 80mph, and that is the essence of the mean value theorem, in a very day to day situation.(20 votes)

- Why doesn't Sal do a video on the proof of Mean Value Theorem?(4 votes)
- There are probably several reasons for this. First, Sal is great but he isn't perfect! It takes time to create videos. I'm sure there are many ideas he or others at KA would love to implement but don't have the time to implement. Also, relatedly, KA focuses on the concepts usually taught in any given class. In my own calculus class, the proof of the MVT was not taught nor was it in the book (unless it appeared significantly later). If this is common, then the majority of students would not need a video covering it. As time is limited, Sal probably considers what videos to make based on what would be the most useful to the most people.(33 votes)

- Did we really need the MVT for this, isn't it just common sense? There's no way you can travel 80mph at any given time under 80mph in erm... less than an hour. Ya know?(7 votes)
- Yes, it's just common sense.

But if you want to learn the Mean Value Theorem why not start with an easy example where you'll also be able to understand the intuition of the problem.(12 votes)

- why mr. khan took a gap in x-axis?(4 votes)
- The time axis represent a continuous increase in t values from the moment of observation which you can put at t = 0 or, as has been done in this case, start your observation at a later instant of time such as 1 PM. Since in this example we are interested in the travel time between 1 PM and 2 PM. We are not focusing on where the car was at 8 AM or 11 AM or 12 PM or even12:59PM. The gap here shows those instants of time before the clock struck 1 PM and we started observing the car which was the position S(1).(7 votes)

- 2:48why did Sal make that gap/hole on the x-axis.(3 votes)
- Sal made the hole on the x-axis in order to show that the graph is not to scale. When looking at the distance between 1st hour and the 2nd hour on the x-axis, it is not the same length as the distance between the 0th hour and the 1st hour. Adding the gap on the x-axis shows us that part of it was omitted when drawing the graph.(4 votes)

- So if you were given a ticket for this, and you argued that you only went at the average speed for a short period of time, they would be right to argue that you went over the average speed?(1 vote)
- Correct, they would be right to assume that you went either 80mph for the full hour, or more probably, went both faster and slower than 80 over the course of the trip.(7 votes)

- What if it isnt continuous?(3 votes)
- What is the difference between position and distance or displacement?(1 vote)
- Suppose you're going from home to school.

Your home is the STARTING POSITION and the school the ENDING POSITION. School is 30m away from home (That means the straight line that connects the two positions is 30 meters long).

You take a path and walk a distance of 35m to get to your destination.

Your total displacement is 30 meters and the total distance travelled is 35 m.**Position refers to single points (the location of a body)**

Displacement is a vector and measures the change in position.

Distance is the length traveled

What happens if you go back home taking the same path?

Now, the total distance travelled is 70m and the total displacement is 0, because you ended in the same position you started (The difference positions is 0).(2 votes)

## Video transcript

You may think that the
mean value theorem is just this arcane theorem that
shows up in calculus classes. But what we will
see in this video is that it has actually been
used-- at least implicitly used-- to give people
speeding tickets. So let's think of an example. So let's say that this is
a toll booth, right here. You're on the turnpike, and
this is a toll booth at point A. And you get your toll-- you
reach it at exactly 1:00 PM, and then the highway's computers
and stuff register that. Let's say you have some type
of-- one of those devices so that when you pay the toll
it just knows who you are and it registers-- it takes
your money from an account someplace. So it sees that you got
there at exactly 1:00 PM. And then, let's say
that you get off of the toll highway,
the turnpike. Let's say you get
off of it at point B, and you get there
exactly 2:00 PM. I'm making these numbers
very easy to work with. And let's say that they
are 80 miles apart. So this distance right
over here is 80 miles. And let's say that
the speed limit on this stretch of highway
is 55 miles per hour. So the question is,
can the authorities prove that you went
over the speed limit? Well, let's just graph this. I think you know
where this is going. So let's graph it. So let's say this right
over here is our position. So I'll call that the
s-axis, s for position. And that's going to be in miles. And s is, obviously, s doesn't
really stand for position. But p, you know, it kind of
looks like rho for density. And d we use for differentials
for distance or displacement. So s is what gets used
for position very often. So let's say s is our position. And let's see,
this is t for time. And let's say this is in hours. And let's see, we care
about the interval from time going from
time 1 to time 2. I'm not really drawing the
axes completely at scale. Would you let me just assume
that there's a gap here just because I
don't actually want to make you think that I'm
drawing it completely at scale. Because I really want to focus
on this part of the interval. So this is time
equals to 2 hours. And so at time equal 1,
you're right over here. And let's say this position is,
we'll just call that s of 1. And at time 2, you're at this
position right over here. You're right over there. And so your position is s of 2. You're at that coordinate
right over there. And that's all we know. That's all we know. Well, we know a
few other things. We know what our change in
time is, it's 2 minus 1. And we know what our
change in position is. We know that our
change in position, which is equal to s of 2 minus
s of 1, is equal to 80 miles. The change in
position is 80 miles. So let me write that, and
we'll just for simplicity assume it was a
straight highway. So our change in distance
is the same as our change in position, same as
change in displacement. So this is 80 miles. And then what is
our change in time? Over our change in time, well
that's going to be 2 minus 1. Which is just
going to be 1 hour. Or we could say that the
slope of the line that connects these two
points-- let me do that in another color--
that's the same color-- the slope of this line right
over here is 80 miles per hour. Slope is equal to
80 miles per hour. Or you could say that your
average velocity over that hour was 80 miles per hour. And what the authorities
could do in a court of law, and I've never heard
a mathematical theorem cited like this, but they could. And I remember reading about
this about 10 years ago, and it was very controversial. The authorities said
look, over this interval, your average velocity was
clearly 80 miles per hour. So at some point in that hour--
and they could have cited, they could have said by
the mean value theorem-- at some point in
that hour, you must have been going at exactly
80 miles, at least, frankly, 80 miles per hour. And it would have been
very hard to disprove because your position
as a function of time is definitely continuous
and differentiable over that interval. It's continuous,
you're not just getting teleported from one
place to another. That would be a
pretty amazing car. And it is also differentiable. You always have a
well defined velocity. And so I challenge anyone. Try to connect these
two points with a continuous and differentiable
curve, where at some point the instantaneous velocity,
the slope of the tangent line, is not the same thing as
the slope of this line. It's impossible. The mean value theorem
tells us it's impossible. So let me just draw. So we could imagine. Say I had to stop to
pay, to kind of register where I am on the
highway, then I start to accelerate
a little bit. So right now, my
instantaneous velocity is less than my
average velocity. I'm accelerating. The slope of the tangent line. But if I want to get
there at that time, and especially because I have
to slow down as I approach it, as I approach the tollbooth. The only way I could connect
these two things-- well let's see, I'm going to have to--
at some point, at this point, I'm actually going faster
than the 80 miles per hour. And the mean value theorem
just tells us, that look, that this function is
continuous and differentiable over this interval. Continuous over the
closed interval. Differentiable over
the open interval. That there's at least one point
in the open interval, which it calls c, so there's
at least one point where your instantaneous
rate of change, where the slope of the
tangent line, is the same as the slope
as the secant line. So that point right
over there, that point looks like that
right over there. And so if this is time c,
that looks like it's like at around 1:15, this-- the
mean value theorem says that at some point, there
exists some time where s prime of c is equal to
this average velocity, is equal to 80 miles per hour. And it doesn't look like
that's the only one. It looks like this
one over here, this could also be
a candidate for c.