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## Modeling with one-variable equations and inequalities

Current time:0:00Total duration:9:00

# Rational equation word problem

CCSS Math: HSA.CED.A.1

## Video transcript

Dominique from Dominique's
Pizza bakes the same amount of pizza every day. She used to spend $8 each
day on using the oven, and $1.50 on ingredients
for each pizza. So $8 each day on
using the oven, and $1.50 on ingredients
for each pizza. One day the price for the
ingredients increased from $1.50 to $2 per pizza. Dominique made some
calculations and found that she should bake
8 pizzas more each day so the expenses for a single
pizza would remain the same. And assume they're
saying the total expenses for a single pizza, because
clearly the ingredients cost is not the same. We're talking about
the total ingredients. So if we were to spread
the cost of the oven across all of the pizzas. Write an equation to
find-- or the total cost for the oven per day, to spread
that across all the pizzas. Write an equation to find out
how many pizzas Dominique baked each day before the
change in price. Use p to represent
the number of pizzas. So let's just think about her
total cost per pizza before and then her total
cost per pizza after if she bakes
8 more pizzas. So before, we're
going to use p to say that's the number
of pizzas she baked per day before the
change in price. So before the change in
price, on a given day, she would spend $8 on the oven
and then $1.50 on ingredients for each pizza. So 1.5, or $1.50, times
the number of pizzas. This would be her total cost
on all the pizzas in that day. It's the oven cost plus
it's the ingredients cost. So if you wanted this
on a per pizza basis, you would just divide
by the number of pizzas. Now let's think
about what happens after the change in price. After the change in price,
her cost per day for the oven is still $8. But now she has to spend $2
per pizza on ingredients. So $2 per pizza. And instead of saying that
she's baking p pizzas, let's say that she's now
baking 8 more pizzas each day. So it's going to be p plus 8. And so this is going to
be her total cost for all of the pizzas she's now baking. And so if you want it on
a per pizza basis, well, she's now making
p plus 8 pizzas, you would divide by p plus 8. And the problem tells
us that these two things are equivalent. Here you had a higher cost
in ingredients per pizzas, but since you are now
baking more pizzas, you're spreading the oven cost
amongst more and more pizzas. So let's think about
what p has to be. p has to be some number,
some number of pizzas, so that these two
expressions are equal. Her total cost per pizza
before, when she only made p, is going to be the same as
her total cost per pizza when she's making
p plus 8 pizzas. So these two things
need to be equal. So we did that first part,
or we did what they asked us. We wrote an equation to find out
how many pizzas Dominique baked each day before the
change in price. And we used p to represent
the number of pizzas. But now for fun, let's
actually just solve for p. So let's just simplify
things a little bit. So this part right over here. Actually, let's just cross
multiply this on both sides. Or another way of thinking
is multiply both sides times p plus 8 and multiply
both sides times p. So if we multiply by p plus
8, and we multiply by p, we multiply by p plus
8, and we multiply by p, that cancels with that. That cancels with that. On the left-hand
side-- so let's see. We have to just do the
distributive property twice right over here. What is p times 8 plus 1.5p? Well, that's going to be 8p. I'm just multiplying the
p times this stuff first. Plus 1.5p squared. And now let's multiply the
8 times both of these terms. So plus 64 plus-- 8 times
1.5, that is 12-- plus 12p. And that's going to be equal
to-- let's see, let's multiply p times all of this business. So that's going to be equal
to 8p-- 8 times p is 8p-- and let's see, I could
distribute these terms and then multiply by p. So 2 times p is 2p, times p is
2p squared, plus 2p squared. And then 2 times 8
is 16 times p is 16p. So now we have--
well, we essentially end up with a
quadratic equation, but let's simplify
it a little bit so that we can either factor it
or apply the quadratic formula. So let's see, let's subtract
1.5p squared from both sides. So subtract 1.5p squared. Actually, let me
just put everything on the left-hand side
just because that might be a little
bit more intuitive. So let's subtract 2p
squared from both sides. Let's subtract 16p
from both sides. We have an 8p and a
12p, and then we're going to subtract a
16p from both sides. And then, actually, let's
subtract an 8p as well from both sides. We have a 16p and an 8p, so that
actually works out quite well. So now we've subtracted
8p from both sides, 16p from both sides. So we've essentially
subtracted all of this stuff from both sides. And we are left with--
let's see, I'll do it in degree order. 1.5p squared minus 2p squared
is negative 0.5p squared. Now let's see, these cancel out. 12p minus 16p is minus 4p. And then we have plus 64. And then that is going
to be equal to 0. And just to simplify
this a little bit, or just to make this
a little bit cleaner, let's multiply both sides of
this equation by negative 2. I want the coefficient
over here to be 1. So then we get p
squared plus 8p. p squared plus 8p is going
to be equal to-- let's see, negative times negative 2. So minus 128-- is
going to be equal to 0. So let's see if we
can factor this. Can we think of two numbers
where if we take their product, we get negative 128? And if we were to add them
together, we get positive 8. So they're going to
have different signs right over here. So let's see, if we say 12
times-- well, let's see. What numbers could this be? So if we were to think about
128 is the same thing as-- 16, let's see, 16 goes into 128. Let me work through this. 16 goes into 128,
does it go 8 times? 8 times 6 is 48. 8 times 10 is 80,
plus 40 is 128. Yep, it goes 8 times. So 16 and 8 seem to work. So if you have positive
16 and negative 8, their product would
be negative 128. So we can factor this out
as p plus 16 times p minus 8 is equal to 0. Now, this is going to be equal
to 0 if at least one of these is going to be equal to 0. So we have two solutions. Either p plus 16 is going to
be equal to 0, or p minus 8 is equal to 0. This one right over here,
subtract 16 from both sides, you get p is equal
to negative 16. Here, you get p is equal to
8, if you add 8 to both sides. Now, we're talking about
a number of pizzas made. So this one doesn't apply. This would be like
Dominique eating 16 pizzas, or somehow destroying
16 pizzas a day. We're not interested
in that solution. So if we want the solution
to the original question, the number of pizzas she made
before the increase in price, she made 8 pizzas per day. So p right over here
needs to be equal to 8. So before the change in price,
she made 8 pizzas a day. After the change in price,
she made 8 more pizzas a day, or 16 pizzas per day.