If you're seeing this message, it means we're having trouble loading external resources for Khan Academy.
If you're behind a web filter, please make sure that the domains
*.kastatic.org and *.kasandbox.org are unblocked.
You've seen parabolas already when you graphed quadratic functions. Now we will look at them from a conic perspective. In particular we will look at them as the set of all points equidistant from a point (focus) and a line (directrix). Have fun!
Sal solves an example task where he adjusting the coefficients of a quadratic equation in a way that shifts and stretches the parabola corresponding to that equation.
Find the equation of a parabola by shifting and scaling the basic parabola y=x^2.
Make one parabola overlap with another by adjusting the focus coordinates and directrix.
Make one parabola overlap with another by adjusting the focus coordinates and directrix. Find the equation of the parabola.