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### Course: Algebra 1 > Unit 6

Lesson 1: Introduction to systems of equations- Systems of equations: trolls, tolls (1 of 2)
- Systems of equations: trolls, tolls (2 of 2)
- Testing a solution to a system of equations
- Solutions of systems of equations
- Systems of equations with graphing: y=7/5x-5 & y=3/5x-1
- Systems of equations with graphing: exact & approximate solutions
- Systems of equations with graphing
- Setting up a system of equations from context example (pet weights)
- Setting up a system of linear equations example (weight and price)
- Creating systems in context
- Interpreting points in context of graphs of systems
- Interpret points relative to a system

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# Interpreting points in context of graphs of systems

Given a graph of a system of equations and a context, practice interpreting what various points represent in that system.

## Want to join the conversation?

- i hate word problems(62 votes)
- This is actually pretty simple. I recommend doing a few problems on your own and then coming back to the video.(2 votes)

- I think I am slowly understanding what this means, however, I feel like I need more practice with it all of it. Also, wherever the variable is on the graph, the number underneath or nearby represents that.(4 votes)
- Simply, Lauren has a sum of money. So she wants to spend this "sum of money" on things like "something." Now the data given about Lauren's situation through Sal's example — we are going to interpret them informally like:

Lauren's sum of money → $ = $220

something → beans = 80 kg

Just remember that we have a couple of constraints that intersect at a given point on the graph. They can be given a description at any point on the graph by Khan Academy even when either of conditions:*have no intersection*,*have intersection.*

Now, we as mathematicians trying to understand Lauren's problem to solve it, we found out that the problem is a bit complicated, but we are not afraid since mathematics supports us with its tools like variables and constants. That; however, is, it is true that Lauren wants to buy a 80 kg of beans, and, it is false that the beans out there in the market found in a single sort of mass. It is, again, true that the constituents here are two different ones in sort, but Lauren does not matter the equality of one sort, say x, over the other one sort, say y. What does matter for Lauren when buying the beans is the the couple of constituents, which are**dark beans + light beans**, has both to be equal to 80 kg in total amount. Again, she does not matter about the amount of dark beans to be equal or less to or more than the amount of light beans, and, it can apply to light beans in reverse too. We are going to see how this no-matter-of-equality relationship relates when we expand on the analysis of data given to Lauren's problem.

If we go back to the context of the problem, we'd see clearly that the price of the dark beans ($3) is higher in one degree than the price of light beans ($2). So it's obvious to learn that Lauren is going to get more light beans than dark beans in kilograms! Again, we as mathematicians have to clear concise to the problem we are stated, which means Lauren's is neither interested in a relation of knowing which constituent x is less than or equal to constituent y, nor are we interested in a relation of knowing which constituent y is more than or equal to constituent x. We mathematicians use less words! We say that Lauren is not interested in a relation of an inequality equation to x and y, like for instance, x ≤ y or x ≥ y, but we are interested in beyond! What's interesting for Lauren's and we is we have constraints: a: 3(60)+ 2(20) = 220, b: 20 + 60 = 80. This what means to have constraints. Remember that the constraints given we need them to be met like 0 = 0. If not, for example, a: 3(10) + 2(96) = 220, b: 10 + 96 = 80, then we are going to use**descriptions**in language instead to show such a relation of a fact deviation.

Now let's go deep into Lauren's problem. The constraints given are**a**and**b**.**a**represents the sum of money in $,**b**represents the amount of beans in kg. So far so good. Remember that both constraints have to intercept at the same point of (x, y) on the graph to have the**a condition 3x + 2y = 220**to be exactly like**a: 3(60) + 2(20) = 220 :: 220 = 220**, and the**b condition x + y = 80 :: 60 + 20 = 80**to be exactly like**80 = 80. *If both constraints don't meet at the same point, this means that *each constraint**would have a point of (x, y) on the graph, like:**a: (x2, y2), and b: (x2, y2).***shows at a point of *(10, 95)* for the

Now let's pick each point on the graph and see how it looks like:

Point *C**a constraint**, and the**b constraint**down right below C shows at point of (10, 70), we get:**point C of (10, 95)***and

a: 3x + 2y = 220

3(10) + 2(95) = 220

220 = 220

b: x + y = 80

10 + 95 = 80

105 = 80

This is if *a**b**were to intersect at (10, 95) whereas only**a**does, and, even though they do intersection at that point the system of equation would dissolve from the side of**constraint b.***and

point down right below C (10, 70)

a: 3x + 2y = 220

3(10) + 2(70) = 220

30 + 140 = 220

170 = 220

b: x + y = 80

10 + 70 = 80

80 = 80

This is if *a**b**were to intersect at (10, 70) whereas only**b**does, and, even though they do intersection at that point the system of our equation would dissolve from the side of constraint a.

So what we can see is**a**and**b**as two constraints fail to intersect at point**C of (10, 95)* to satisfy the system of our equation. In description, we would say about point C that, *Lauren spends the intended amount of money and buys more than the intended amount of beans.* The point *down right below C at (10, 70)* also fails like the one above it that C, which we would describe it like "Lauren spends less than the intended amount of money and buys the same intended amount of beans.***and their descriptions: (Notice that I am using the same descriptive language by Khan Academy)

Let's continue with other the points of *D, F, and E

point D of (20, 60)

a: 3x + 2y = 220

3(20) + 2(60) = 220

60 + 120 = 220

180 = 220

b: x + y = 80

20 + 60 = 80

80 = 80**Description****Lauren spends less than the intended amount of money and buys the same intended amount of beans.***

point F of (30, 30)

a: 3x + 2y = 220

3(30) + 2(30) = 220

90 + 60 = 220

150 = 220

b: x + y = 80

30 + 30 = 80

60 = 80

*Description**Lauren spends less than the intended amount of money and buys less than the intended amount of beans.***

point E of (60, 20)

a: 3x + 2y = 220

3(60) + 2(20) = 220

180 + 40 = 220

220 = 220

b: x + y = 80

60 + 20 = 80

80 = 80

*Description**Lauren spends the same intended amount of money and buys the same intended amount of beans.***and

Finally, We can see how *the point E of (60, 20),* that by which both constraints of *a**b**are intersected.(30 votes)

- what is this i dont get it(8 votes)
- man im poor in points(4 votes)
- if you rewind the video to a few seconds before it ends and watch those few seconds over and over its an infinite point glitch!(7 votes)

- I think I am slowly understanding what this means, however, I feel like I need more practice with it all of it. Also, wherever the variable is on the graph, the number underneath or nearby represents that.(5 votes)
- You can do it! Practice until you can't get it wrong :)(2 votes)

- this is used in economics XD(5 votes)
- What doesn't quite make sense to me is the fact that the graph represents light (y) and dark (y), however the green graph represents price, which is not represented in this matrix. Why does this work?(5 votes)
- What does dark and light represent?, so confusing(4 votes)
- why wouldn't Lauren want to get the number of beans she needs for less money?Unless she needs a specific number of Light and Dark beans.(4 votes)
- awesome! What if I am Lauren's boss, and I give her 120 $ to buy 80 kg of beans, how could she solve it?(2 votes)
- Even the cheapest beans cost 2 dollars per kilogram, so Lauren can at most get 60 kg of beans for $120.(2 votes)

## Video transcript

- [Instructor] We're told
that Lauren uses a blend of dark roast beans and light roast beans to make coffee at her cafe. She needs 80 kilograms of beans
in total for her next order. Dark roast beans cost $3 per kilogram, light roast beans cost $2 per kilogram, and she wants to spend $220 in total. And they tell us here's a graph that shows a system of
equations for this scenario where x is the number of kilograms of dark roast beans she buys and y is the number of kilograms of light roast beans she buys. All right, let me scroll down
so we can take a look at this. And so sure enough, so this blue line, and I'll write it out in blue, this x is the number of
kilograms of dark roast beans, y is the number of kilograms
of light roast beans, and she wants to buy a
total of 80 kilograms. That's what they told us up here. We can go back to look at that. She needs, I'll underline this in blue. She needs 80 kilograms of beans. So that constraint that
the sum of the kilograms of dark and light is equal to 80, that's represented by this equation. And if we were to graph it, that is this blue line right over here. And then this other constraint, three x, well, the dark roast beans
cost $3 per kilogram, so three x is how much
she spends on dark roast. Two y is how much she
spends on light roast 'cause it's $2 per kilogram. And 220 is the amount
that she spends in total. And they tell us that up here. Dark roast beans cost $3 per kilogram, light roast beans cost $2 per kilogram, and she wants to spend $220. So this equation is
another way of expressing what I just underlined up here in green. And the green line shows all of the x y combinations that
would match these constraints. And so now let's do something interesting. They've labeled some points
here, point C, D, F, and E. And we're gonna think about what do each of these points represent? So for example, this point
C that is on the green line, but it sits above the blue line, what does this tell us? What does this point C represent? Pause this video and think about it. Well, if we're on the green line, that means that the amount
that she spends on dark roast plus the amount that she spends
on light roast is adding up to exactly $220. So she's definitely spending $220 at C, but how many total kilograms is she using? Well, the fact that for this given x, we're sitting above the line, that means that she's not
using exactly 80 kilograms. And we can see that over here. She's using, looks like
10 kilograms of dark, and it looks like something
like 95 kilograms of light. If you were to add those
two points together, it looks like she's using
something closer to 105 kilograms. So point C is a situation where she is spending exactly $220, but she's using more than 80 kilograms 'cause it's not meeting
this second constraint. It's sitting above that line. Now let's think about point D. What does that represent? Pause the video and
try to figure that out. Well, because we sit on the blue line, that means that we are
meeting this constraint that the kilograms of
dark and light combined is equal to 80 kilograms. So she's using exactly 80 kilograms here, but what about her spending? Well, because this point
lies below the green line, that tells us that we are spending less than $220. And we could even try it out. Three times 20 plus two times 60 is what? 60 plus 120 is $180. And so this is a point where
we're meeting this constraint, but we're not meeting this constraint. We're underspending right over here. Now, what about point F? Well, point F sits below
both of these lines. So pause your video and
think about what that means. Well, if we're sitting
below both of these lines, that means that neither
are we spending $220, nor are we using 80 kilograms. And you can see that if you
actually look at the numbers. You don't have to do this, but this is just to make
you feel good about it. It looks like she is
using 30 kilograms of dark and 30 kilograms of light,
so in total she is using, so this is a situation where she's using 60
kilograms in total, not 80. And so that's why we're not
sitting on this blue line. And if you look at how
much she's spending, she has 30 kilograms of each, so three times 30 plus two times 30, that's going to be 90 plus 60. That's also less than 220, and so that's why we see this
point is below these lines. And then last but not least,
what does point E represent? Well, point E sits on both of these lines, so that means that it meets
both of these constraints. This is a situation where
she is spending exactly $220, and the total number of
kilograms she's using of dark and light is exactly 80. And so if we wanted to
say, hey, what combination of dark and light would she need in order to meet both
constraints, E represents that, the intersection of these two lines.