# Analyzing tables of exponentialÂ functions

CCSS Math: HSF.IF.B.4

## Video transcript

- [Voiceover] Let's say
that we have an exponential function, h of n, and since it's an exponential function it's going to be in the
form a times r to the n, where a is our initial value and r is our common ratio, and we're going to assume
that r is greater than zero. And they've given us some
information on h of n. We know that when n is equal to 2, h of 2 is 144, that h of 4 is 324, that h of 6 is 729. So, based on the information here, let's see if we can actually figure out what a and r are going to be. And like always, pause the
video and try to give it a go. All right, now let's do this together. So I'm going to focus on r first. The common ratio and if we had successive n's. If we had h of 3, then
we could just find the ratio between h of 3 and h of 2 and r would just come out of that, or if the ratio between h of 4 and h of 3, we could solve explicitly for r, but we can get pretty close to that. We can just find the ratio between h of 4 and h of 2. So, h of 4, the ratio between h of 4 and h of 2 is going to be equal to, well, we know h of 4 is 324, and h of 2 is 144, and we could simplify this a little bit. Let's see, if we, if we simplify this, we would get, they're both divisible by 2. If we divide them both by 2, this one in the numerator, 324 divided by 2 is 162. 144 divided by 2 is 72. Let's see, we can divide by 2 again. 81 over 36. Divide by 2, actually, no, we can't
divide by 2 anymore, but we can divide by 9 now, so 81 divided by 9 is 9, and 36 divided by 9 is 4. So this thing can be rewritten as 9/4, but we could also rewrite this ratio by using, using this form of an
exponential function, so we could also say that
this is going to be equal to, h of 4 is going to be a times r. Now n is 4, so r to the 4th power, and h of 2 is going to be
a times r to the 2nd power. A times r to the 2nd power, and this simplifies nicely, a divided by a, cancels to just 1, and r to the 4th divided by r-squared, well that's going to be
r to the 4 minus 2 power, or r, it's going to be r to the 2nd power, it's going to be r-squared, and so we have a nice
little equation set up. R-squared needs to be equal to 9/4. So let me write that down. R-squared is equal to 9/4, and r needs to be greater than zero, so we could just say r is
going to be the principal root of 9/4, which is equal to 3/2. So we were able to figure out r. So now how do we figure out, how do we figure out a? Well, there's a couple of ways to do it. You can think about a is
going to be what h of zero is equal to, so we could do, I guess we could call it a tabular method, where, let me set up a little table here. So, a little table, so if this is n and this is h of n, so n is zero, we don't know what h of zero is just yet, it's going to be a. We don't know what h of 1 is yet. We do know that h of 2 is 144. And we do know, since
the common ratio is 3/2, if we take h of 1 and
we multiply it by 3/2, we're going to get h of 2, and if we take h of zero
and multiply it by 3/2, we're going to get h of 1. So, h of 1 is going to
be 144 divided by 3/2. So let's write that down. H of 1 is equal to 144 divided by 3/2, which is going to be 144, 144 times 2 over 3, and let's see, 144 divided by 3 is going to be equal to, is it, let's see, one 3 goes into, I'll just do this by hand, my brain doesn't work that well while I'm making videos. 3 goes into 14 four times, 4 times 3 is 12, subtract, so it's going to be, I see, it's going to be 48. 3 goes into 24 eight times. 8 times 3 is 24, you have no remainder, so, this is going to be 48 times 2, which is going to be equal to 96 so this is going to be 96, and so if we want to figure out h of zero, we just divide by 3/2 again, so, h of zero is 96 divided by 3/2 which is equal to 96 times 2 over 3. 96 divided by 3, let's see, it's going to be 32, so this is going to be 32 times, did I do that right? Yup, 32 times 2 which is equal to 64. 64. And so, just like that,
we've figured out that a is equal to 64, and r, and r is equal to 3/2. So we can write h of n, we can say that h of n is equal to 64, is equal to 64 times 3/2, times 3/2, our common ratio, to the nth power. Now, there's another way that
we could have tackled this instead of this tabular method. We could have just solved for a now, since we know r. We know, for example, we know for example that h of 2 which is going to be equal to a times, we know what our common ratio is, it's 3/2 to the 2nd power, is going to be equal to 144. And so, we could say a times 9 over 4 is equal to 144, and so we can multiply both
sides times the reciprocal of 9 over 4, so we multiply both sides times 4 over 9, times 4 over 9, and that cancels with that, that cancels with that, and we are left with a is equal to, well let's see, 144 divided by 9 is going to be, is going to be, I want
to say it's equal to 16? Is that right? I think that is right. Yup, and then 16 times 4, so this is going to be 16 and 1, 16 times 4 is 64, which is exactly what we got before, and so this actually, this method, now that I look at it, is actually a good bit easier, but they're equivalent, and I like this one because
you get to see the common ratio in action, and you get
to see that the initial value is the initial value. It is h of zero, but either way, once you figure out r, and you know one of the h of, you know what the function is at a value, you can solve for a, and frankly, if you
knew a and you knew what the function was for a given n, you could likewise solve for r. So hopefully you enjoyed that.