Algebra (all content)
Constraining solutions of two-variable inequalities
Sal determines which x-values make the ordered pair (x,-7) a solution of 2x-7y<25, both algebraically and graphically.
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- can you please explain how you got the x on the first one(10 votes)
- Sal was solving for y so he got the x value.(0 votes)
- Why not greater than or equal to 7 in the second example(4 votes)
- The dotted line means that it is a strict inequality which means that any point that is lying on that line will not be part of that inequality. And since 7 lies on that line, it isn't part of the inequality.
Hope this helps :-)(8 votes)
- Why is the inequality's line dotted? I was hoping he would explain, but he didn't up until now...(2 votes)
- This is to show that the solutions include everything up to that line, but not the line itself. If it were "greater than or equal to," the line would be solid, since the numbers on the line are included in the solutions.(3 votes)
- I don't mean this in a mean way but when would I have to use this kind of math. Like can you give me a real life situation.(2 votes)
- Any time you have to stay under budget on a project. Let's say you need to make a thing for less than 25 bucks. It has two parts (the x and the y). You know the cost of one of the parts (the y is -7). You need to know how much you can spend on the other part.
Hey I notice that you wrote this question five years ago :) What do you think about this kind of math, as you look at your real life situations now?(1 vote)
- how do you do algebra anyway?(2 votes)
- how do you even do algebra(2 votes)
- Then how would you solve 7x+5y≥5(1 vote)
- What does the shaded area represent?(1 vote)
- The shaded area represents all possible solutions for the inequality.(1 vote)
- What are Constrains and what do they mean in a word problem/equation?(1 vote)
- Why did he point the order pair (-5,6)?(1 vote)
- In that problem, any point in the shaded area of the graph would be a solution to the inequality. Sal was just trying to highlight that concept before moving on to the details asked in the question above the graph.(1 vote)
- [Voiceover] "Which x-values make the ordered pair "X, comma negative seven, a solution of the "following inequality?" The inequality is two X minus seven Y is less than 25. And so they give us some choices, and I encourage you to pause the video and see if you can figure it out on your own. All right, now let's work through it together. They're constraining that Y is going to be equal to negative seven. And so if we make that constraint, we can replace this Y with a negative seven. So we can rewrite the inequality as two X minus seven times negative seven, since we're constraining Y to be negative seven, is less than 25. And so this is going to be two X minus negative 49, or two X plus 49, is less than 25. Now if I just wanna isolate the X on one side, which we see for these inequalities up here, so we could subtract 49 from both sides. So subtracting 49 from both sides, we get two X is less than, let's see, 49 minus 25 would be positive 24, so this would be negative 24. Now to isolate the X, we just divide both sides by two and we're not gonna change the inequality, since we are multiplying or dividing by a positive value. Positive two. So this is going to be X is less than negative 12. And lucky for us, this is a choice. So as long as, if Y is equal to negative seven, as long as X is less than negative 12, we will satisfy this inequality. Let's do another one of these. And this one is a little bit more visual. So "Which Y-values make the ordered pair," so in the last one we constrained what Y was, and we figured out what X values would satisfy this inequality. Now we're going the other way around. We're constraining X and we're saying, what Y values would make the ordered pair true? Or make it a solution? "Which Y values make the ordered pair 5 comma Y "a solution of the inequality represented by the graph below?" So they didn't give it to us algebraically, they gave it to us visually. And so to be a solution, that means we have to be in this blue area. So this pair, so negative five, comma six. That would be a solution to the inequality being depicted. Something that sits exactly on the line, this would not be a solution, because notice the line, as you can see this lower boundary line, is a dashed line. If it was filled in, than anything on the line would be a solution. But since it's dashed, things on the line aren't solutions. It's only things that are above the line are going to be solutions. So let's see what they're asking us to think about. So they're saying, they're constraining X to be equal to five. So X equals five is everything, let me see if I can draw this. X equals five is everything on that line right over there. Now, if we assume that X equals five, we're gonna be someplace on this line, how do we have to constrain Y to make sure that we are in the solution? Well, we have to constrain Y so that we are above the line, for X equaling five, just to be clear. So we have to be above, our possible points are gonna be the ones once again, we're constraining X equals five, the possible points are the ones, that I'm showing in magenta. And actually I could keep going if I want to. So Y is going to have to be greater than, it can't be greater than or equal to seven, it has to be greater than seven. If it was greater than or equal to seven, we'd be including the point on the line, but I already talked about this being a dashed line so we don't want to include the points on the line. We only want to include the points above the line. So Y is going to be greater than seven which is this choice right over there. If X is equal to five, as long as Y is greater than seven, we are going to be in the solution set.