Sal solves a few quadratic inequalities by moving all terms to one side of the inequality and graphing the resulting expression. Created by Sal Khan.
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- What does it meant at9:06?? What is the point on the curve?(12 votes)
- At9:06, Sal highlites the curve under the x-axis, but remember that the entire curve is f(X) (which is also called y). Since you're dealing with a curve rather than a straight line, you use f(x). A straight line is simple, so y works, but curves are more complicated and f(x) is a more advanced tool. Keep it up and you'll gradually understand. It takes time and practice, but it's worth it.(19 votes)
- Why is the y intercept -6? Sal mentions it at1:52(13 votes)
- How do you solve this inequality x^2+3x is greater or equal to -2. I've tried doing it and got x is greater or equals to -2 and x is greater or equals to -1 but that is no the right answer. Please help(3 votes)
x² + 3x ≥ -2
=> x² + 3x + 2 ≥ 0
=> x² + 2x + x + 2 ≥ 0
=> x(x + 2) + 1(x + 2) ≥ 0
=> (x + 1)(x + 2) ≥ 0
=> x ∈ [-∞, -2]⋃[-1, ∞]
x < -2or
x > -1.(9 votes)
- Why is F(x)>0??? I thought F(x) is changed into 0? So,how can F(x)>0?? Confusing.(5 votes)
- In solving quadratic equalities Sal was showing how to solve for f(x) = 0. Meaning the points at which the f(x) line crosses or intersects the x-axis (=0). In solving quadratic INequalities Sal shows how you can solve for f(x) > 0 or f(x) < 0. Meaning the x coordinates at which point the f(x) line is above (>) or below (<) the x-axis (0).
The two are related because the points where the f(x) line intersect the x-axis (=0) are also the same points between which the f(x) line rises above (>) or falls below (<) the x-axis (0).(3 votes)
- Why does he put the vertex of the parabola on the y-axis? Shouldn't it be @ (-0.5,-6.25)? Or is he just making a rough drawing... not intentional?(6 votes)
- Do you think that graph can be misleading especially to those who are beginner. From my point of view it looks like that the vertex is (0, -6)(1 vote)
- Why do you have to change the sign > to <?? It looks something like you change both sides equations...but instead of doing that,you change the signs? Why not use = instead of </>?(at5:13)(2 votes)
I use a simple example whenever I can.
Say 10>0. If you change the sign on 10, then -10<0.
The same exact change happens if there are multiple numbers, as long as you change all of the signs.
BTW, if you have numbers on both sides of inequality, say, 10>9, you just change signs on both sides and flip the arrow. -10<-9. Hope this helps.(6 votes)
- I dont understand how to graph Y >X^2+4(3 votes)
- Also, when an inequality is solved for y, you can interpret "y >" as "above the line" and "y <" as "below the line". Just be careful, as a negative coefficient will reverse this logic. When in doubt, test points!(4 votes)
- What point is the axis of symmetry?(2 votes)
- Why is the vertex -6 instead of -b/2a or - 1/2 ?(2 votes)
- Sal tells you at about1:55that -6 is the y-intercept (the point (0, -6). He then explicitly tells you that it is not the vertex. The point is close to the vertex, but it is not the vertex.
You can find the x-value of the vertex can be found using -b/2a = -1/2.
Then, you can find the y-value of the vertex by plugging in x = -1/2(4 votes)
Welcome to the presentation on quadratic inequalities. Before we get to quadratic inequalities, let's just start graphing some functions and interpret them and then we'll slowly move to the inequalities. Let's say I had f of x is equal to x squared plus x minus 6. Well, if we wanted to figure out where this function intersects the x-axis or the roots of it, we learned in our factoring quadratics that we could just set f of x is equal to 0, right? Because f of x equals 0 when you're intersecting the x-axis. So you would say x squared plus x minus 6 is equal to 0. And you just factor this quadratic. x plus 3 times x minus 2 equals 0. And you would learn that the roots of this quadratic function are x is equal to minus 3, and x is equal to 2. How would we visualize this? Well let's draw this quadratic function. Those are my very uneven lines. So the roots are x is equal to negative 3. So this is, right here, x is at minus 3y0 -- by definition one of the roots is where f of x is equal to 0. So the y, or the f of x axis here is 0. The coordinate is 0. And this point here is 2 comma 0. Once again, this is the x-axis, and this is the f of x-axis. We also know that the y intercept is minus 6. This isn't the vertex, this is the y intercept. And that the graph is going to look something like this -- not as bumpy as what I'm drawing, which I think you get the general idea if you've ever seen a clean parabola. It looks like that with x minus 3 here, and x is 2 here. Pretty straightforward. We figured out the roots, we figured out what it looks like. Now what if we, instead of wanting to know where f of x is equal to 0, which is these two points, what if we wanted to know where f of x is greater than 0? What x values make f of x greater than 0? Or another way of saying it, what values make the statement true? x squared plus x minus 6 is greater than 0, Right, this is just f of x. Well if we look at the graph, when is f of x greater than 0? Well this is the f of x axis, and when are we in positive territory? Well f of x is greater than 0 here -- let me draw that another color -- is greater than 0 here, right? Because it's above the x-axis. And f of x is greater than 0 here. So just visually looking at it, what x values make this true? Well, this is true whenever x is less than minus 3, right, or whenever x is greater than 2. Because when x is greater than 2, f of x is greater than 0, and when x is less than negative 3, f of x is greater than 0. So we would say the solution to this quadratic inequality, and we pretty much solved this visually, is x is less than minus 3, or x is greater than 2. And you could test it out. You could try out the number minus 4, and you should get f of x being greater than 0. You could try it out here. Or you could try the number 3 and make sure that this works. And you can just make sure that, you could, for example, try out the number 0 and make sure that 0 doesn't work, right, because 0 is between the two roots. It actually turns out that when x is equal to 0, f of x is minus 6, which is definitely less than 0. So I think this will give you a visual intuition of what this quadratic inequality means. Now with that visual intuition in the back of your mind, let's do some more problems and maybe we won't have to go through the exercise of drawing it, but maybe I will draw it just to make sure that the point hits home. Let me give you a slightly trickier problem. Let's say I had minus x squared minus 3x plus 28, let me say, is greater than 0. Well I want to get rid of this negative sign in front of the x squared. I just don't like it there because it makes it look more confusing to factor. I'm going to multiply everything by negative 1. Both sides. I get x squared plus 3x minus 28, and when you multiply or divide by a negative, with any inequality you have to swap the sign. So this is now going to be less than 0. And if we were to factor this, we get x plus 7 times x minus 4 is less than 0. So if this was equal to 0, we would know that the two roots of this function -- let's define the function f of x -- let's define the function as f of x is equal to -- well we can define it as this or this because they're the same thing. But for simplicity let's define it as x plus 7 times x minus 4. That's f of x, right? Well, after factoring it, we know that the roots of this, the roots are x is equal to minus 7, and x is equal to 4. Now what we want to know is what x values make this inequality true? If this was any equality we'd be done. But we want to know what makes this inequality true. I'll give you a little bit of a trick, it's always going to be the numbers in between the two roots or outside of the two roots. So what I do whenever I'm doing this on a test or something, I just test numbers that are either between the roots or outside of the two roots. So let's pick a number that's between x equals minus 7 and x equals 4. Well let's try x equals 0. Well, f of 0 is equal to -- we could do it right here -- f of 0 is 0 plus 7 times 0 minus 4 is just 7 times minus 4, which is minus 28. So f of 0 is minus 28. Now is this -- this is the function we're working with -- is this less than 0? Well yeah, it is. So it actually turns that a number, an x value between the two roots works. So actually I immediately know that the answer here is all of the x's that are between the two roots. So we could say that the solution to this is minus 7 is less than x which is less than 4. Because now the other way. You could have tried a number that's outside of the roots, either less than minus 7 or greater than 4 and have tried it out. Let's say if you had tried out 5. Try x equals 5. Well then f of 5 would be 12 times 1, right, which is equal to 12. f of 5 is 12. Is that less than 0? No. So that wouldn't have worked. So once again, that gives us a confidence that we got the right interval. And if we wanted to think about this visually, because we got this answer, when you do it visually it actually makes, I think, a lot of sense, but maybe I'm biased. If you look at it visually it looks like this. If you drive visually and this is the parabola, this is f of x, the roots here are minus 7, 0 and 4, 0, we're saying that for all x values between these two numbers, f of x is less than 0. And that makes sense, because when is f of x less than 0? Well this is the graph of f of x. And when is f of x less than 0? Right here. So what x values give us that? Well the x values that give us that are right here. I hope I'm not confusing you too much with these visual graphs. And you're probably saying, well how do I know I don't include 0? Well you could try it out, but if you -- oh, well how come I don't include the roots? Well at the roots, f of x is equal to 0. So if this was this, if this was less than or equal to 0, then the answer would be negative 7 is less than or equal to x is less than or equal to 4. I hope that gives you a sense. You pretty much just have to try number in between the roots, and try number outside of the roots, and that tells you what interval will make the inequality true. I'll see you in the next presentation.