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## Algebra (all content)

### Course: Algebra (all content) > Unit 3

Lesson 14: Linear models word problems# Linear models word problem: book

Sal solves a word problem about a person reading a book, The solution involves the modeling of the situation as a linear function.

## Want to join the conversation?

- why didn't you dived the the amount of pages the book have with page it take him one hour to read?(5 votes)
- I'm working my way from basic arithmetic up through vector calculus as a thorough review of my middle school, high school, and college math. Now that I'm in the Algebra section, I've notice that the word problems have gone full metric leaving the US standard units out. I miss the US units. They are so elegant, beautiful, warm and familiar. Will I ever see them again in any of the Khan Academy videos and problems? As a prospective high school teacher, I might actually browse the 'Common Core' modules. I sure hope to find some US units there. I'd hate to think they're not expected to be taught in the future when much of our industry uses this system of weights and measures. Thanks! -John in Seattle(3 votes)
- Sometimes, they do use "US" units(called English units), however for the most part they use metric. Mostly only the united states, Liberia, and Burma us English units of measurements. Due to the internationality of this website, they mostly use metric. Metric units are also the units most commonly used for science and engineering. Besides all that metric is easier to use and convert than the English system.(4 votes)

- I was taking one of these tests about linear equations after watching the videos, I am still so confused. Like how does 3x=7y or something like that seem right when you put it down on the grid but its wrong and its like on the other side and is at 8y, 11x?(4 votes)
- How can one decide which is the Y equivalent and which is the X equivalent on the "y=mx+b" general formula?(3 votes)
- The x is the independent, and the y is the dependent variable. Which depends on the other. So if every minute you gain 6 pounds, the x is the time in minutes and the y is the pounds.Hope this helps.(2 votes)

- I just don't get how to solve my problem. I watched the math video about it but I'm not understanding.(3 votes)
- what if there were more than ten hours.... like 40 hours.... is there an easier and faster way to get the answer than constantly subtracting or adding 55.(3 votes)
- i understand the first part of the lesson but once he talks about how to find how long it took the person to read the book I just completely got confused. HELP!(1 vote)
- First you have to understand that at 4 hours, Naoya has 330 pages left to read. He also reads at a constant rate of 55 pages an hour. So, as every hour passes by, the number of pages will decrease by 55. A quicker way to do this than just subtracting 55 from each new number that represents pages left, you can just divide 330 by 55. This gets you to 6. You also have to realize we didn't start at 550, the total number of pages in the book, so we have to add 6 hours to the number of hours it took to get to 330 pages left, which is 4 hours. An added 6 hours + 4 hours that Naoya was reading gets you to 10 hours. Dividing 550 (total # of pages) by 55 (constant rate of pages per hour) will also get you the total number of hours needed to read the book. Hope you found this useful.(5 votes)

- How do I watch a video I have already watched? It doesn't seem to be allowing me.(3 votes)
- Just pull the circle (that tells you where you are in the video) back to0:00.(1 vote)

- What's the difference between a linear model, and linear problems? Or linear model and linear equation problem?(1 vote)
- I guess you mean by linear problem that you mean a linear function. The difference is the correlation coefficient. A linear function has a correlation coefficient of 1 (or -1) while a linear model can have a correlation coefficient less than one, the closer it is to 1, the closer that the scatterplot is to the linear model of an equation. Thus, a linear function is a specific type of linear models, but there are many more linear models that are not linear functions. See video about correlation coefficient;

https://www.khanacademy.org/math/probability/scatterplots-a1/creating-interpreting-scatterplots/v/correlation-coefficient-intuition-examples(2 votes)

- I dont get how he get the 10, how did he get 10 hours(0 votes)
- From the table of values Sal created, he can tell that in each hour 55 pages get read. He knows there are 550 pages in the book. Use division 550/55 = 10 hours to read the entire book.

Hope this helps.(3 votes)

## Video transcript

- [Voiceover] Naoya read
a book cover to cover in a single session, at a
rate of 55 pages per hour. 55 pages per hour. After reading for four hours,
after reading for four hours, he had 330 pages left to read. How long is the book in pages and how long did it take Naoya to read the entire book? Well there's a bunch of ways
that we could approach this. Like always, pause the video
and try to figure it out. But I will go with one
way first, and then maybe I'll tackle it another way. So one way is, let's just
set up a little table here. And on one column, let's think about, let's think about how long Naoya has read in hours, so we'll just call that "time." "T" for time in hours. This is how long he has
read, and in this column, this is how much he has left to read. So let's just write
that "L," left to read. And then this is going
to be given in pages. This is going to be given in pages. So lets see, we don't know at zero hours, we don't know how many
pages he has left to read, at, if we knew that, at zero
hours, before he's read, the pages left to read, that's
gonna be the entire book. So that would answer this
question, "How long is the book?" So this is gonna be interesting. We don't know what happens at one hour, after two hours, after three hours. But they do tell us, that
after reading for four hours, after reading for four
hours, he had 330 pages left to read. So after four hours, he had 330 pages, 330 pages left to read. So, based on this, and the fact that he's reading at 55 pages per hour, can we back up to figure out all of this? Well remember, every hour that goes by, every hour that goes by,
he has read 55 pages. So if he's read 55
pages, remember this 330, this isn't how many pages he's read, this is how many he has left to read. So after every hour he has
55 fewer pages to read. So at three hours, he should
have 55 more pages to read. So this should be, at
three hours, 330 plus 55 would be 385. Now let's see whether this makes sense. So when our change in time, this triangle is just the Greek letter
Delta, means "change in." When our change in time is
plus one, plus one hour, our change in pages left
to read is going to be equal to negative 55 pages. And that makes sense,
the pages left to read goes down every hour. We're measuring not how much he's read, we're measuring how much
he has left to read. So that should go down
by 55 pages every hour. Or if we were to go
backwards through time, it should go up. So at two hours he should
have 55 more pages to read. So what's 385 plus 55? We'll let's see, 385 plus
5 is 390, plus 50 is 440. So he'd have 440 pages, and
all I did is I added 55. And then, after reading for one hour, he would have 55 more pages than after reading for two hours. So 440 plus 55 is 495. And then before he started reading, or right when he started reading, he would have had to
read even 55 more pages, 'cause after one hour, he
would have read those 55 pages. So 495 plus 55 is going to be, let's see, it's gonna be, add 5, you get to 500 plus another 50 is 550 pages. So at time equals zero
had had 550 pages to read. So that's how long the book is. But how long does it take
Naoya to read the entire book? Well we could keep going. We could say, "Okay, at the fifth hour, "this thing's gonna go down by 55." So let's see, if this goes down by 50, if this goes down by 50,
we're going to get to 280, but then you go down five more, it's gonna go to 275, and we could keep going on and on and on. Or we could just say, "Look." "He's got 330 pages left
to read, and he's gonna," Let's see, let me write this,
let me write the units down. "Pages, and he's reading at
a rate of 55 pages per hour, "pages per hour, this is the same thing, "this is going to be equal to 330 pages "times one over 55 hours per page." I'm dividing by something,
the same thing as multiplying by its reciprocal, so 55 pages per hours, if you divide by that, that's the same thing as multiplying by 1/55th of an hour per page,
is one way to think about it. And so what do you get? The pages cancel out,
pages divided by pages, and you have 330 divided by 55 hours. 330 divided by 55 hours. And what's that going to be? Let's see, 30 divided by 5 is 6, 300 divided by 50 is 6,
so this is going to be equal to 6 hours. Now we have to be very
careful, you might want to write six hours here, but this is six hours after this point. Six hours after that point. So in total, it's going
to take him ten hours. At four hours, he had
330 pages left to read and then there was six more hours to finish those 330 pages. So it's gonna take a total of ten hours. And we could also see if this makes sense. If he reads 550 pages in ten hours, If he reads 550 pages in ten hours, in ten hours, what's his rate of reading? Well, 550 divided by 10, that's gonna be the same thing as 55 pages per hour. Which is consistent
with what we just read, that he reads at 55 pages per hour. Now another way that you
could have tackled this, you could say, "Hey, this in gonna be "a linear equation!" If you're well versed
with your linear equations you could say, "Look, he's
reading at a constant rate." And if we're talking about, let's say, let me just set up a function here, we could say left to read,
as a function of time, is going to be equal to,
he's reading at a rate of 55 pages per hour, so the
amount he's left to read is gonna go down by 55 pages per hour. So it's gonna go down
55, 55 pages every hour. So you could write it like that, plus it's whatever the initial number of pages were. Plus whatever the initial
number of pages were. And then you could use this information right over here to solve for b. We know that when time
is equal to four hours, we know that when, let
me do it in that color. We know that when time
is equal to four hours, that the pages left to read are 330. Pages left to read are 330, and so you get 330 is equal to, let's
see, negative 55 times 4 is negative 220. Negative 220 plus, negative 220 plus b, plus b, and then if you
add 220 to both sides, 220, add 220, to both
sides, you're going to be left with, on this
side, you're gonna get 550 is equal to, these cancel
out, they add up to zero, is equal to b. And so the function
that describes how much he has left to read,
the amount he has left to read is a function
of time, is, well he's reading 55 pages per hour, so the amount he has left to read's
gonna go down every hour, that's why we have that negative there. So the negative 55 pages per hour, times the number of hours, plus 550. So if someone said, "Well
how long is the book?" Well that's going to be L of zero. That's going to be how many pages he has left to read at time zero. And we see that L of
zero is going to be 550. When T is equal to zero,
let me write this down, L of zero is going to be equal to 550. When T is equal to zero,
this term goes away and you just have 550 pages. And, just like that,
we could have answered this question. And then you could say,
"Well look, if the book "is 550 pages, and if he's
reading at 55 pages per hour, "how many hours is it gonna take?" Well 550 pages divided
by 55 pages per hour is going to get you 10 hours. And we could have done that here actually, now that I think about it. Instead of saying 330
pages divided by 55 pages per hour, and say ,"Hey,
that's gonna take us "six more hours from this point." We already knew this,
and we could have said, "Look, if we have 550 pages to read, "and we're reading at 55 pages per hour, "it's gonna take us ten hours." So you see, there's a
ton of different ways to solve these problems. And they're all really,
at the end of the day, representing the same thing. That's what's neat about mathematics. They're just ways of representing how to think about things, and
at the end of the day we're really just thinking
about the same problem, just representing it with different ways and different symbols.