Solving exponential equations with logarithms (Algebra 2 level)
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Solving exponential equations using logarithms: base-10
Voiceover:Solve the equation for T and express your answer in terms of base 10 logarithms. And this equation is 10 to the 2T - 3 is equal to 7. We want to solve for T in terms of base 10 logarithms. So let me get my little scratchpad out and I've copied and pasted the same problem. So I'm just going to rewrite it, so they have 10 to the 2T-3 is equal to 7. Actually, let me color code this a little bit. So 10 to the 2T - 3 is equal to 7. So this is clearly an exponential form right over here. if we want to write it in logarithmic form, where we could, that'll essentially allow us to solve for the exponent, so we could say, this is the exact same truth about the universe as saying that the log base 10 of 7 is equal to 2T - 3. Let's just make sure that makes sense, this is saying 10 to the 2T - 3 = 7 This is saying that the power that I need to raise 10 to to get to 7 is 2T - 3, or 10 to 2T - 3 power is equal to 7. So these are equivalent statements. What this form does is it starts to put it into a form that's easier to solve for T, now if we want to solve for T, we can add 3 to both sides. So if we add 3 to both sides, we are going to get, log base 10 of 7 + 3, plus 3. And this +3 is of course outside of the logarithm to make it clear, it's just like that. And on the right hand side this is going to be equal to, this is going to be equal to just 2T. And now to solve for T we just divide both sides by 2. So if we divide both sides by 2 we get, T is equal to all of this business, log base 10 of 7 + 3 all of that over 2, so let me see if I can remember this, and write it in the actual box that they gave us. So we want to do log base 10 of 7 and then that + 3 yup it's formatting it right, divided by 2. So that's what I'm claiming the T is equal to in terms of Base 10 logarithms. So let me check my answer and I got it right.