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## Algebra (all content)

### Course: Algebra (all content) > Unit 16

Lesson 11: Challenging complex number problems# Challenging complex numbers problem (1 of 3)

Paper 1 Problem 39 from the challenging 2010 IIT JEE exam, about complex numbers. Created by Sal Khan.

## Want to join the conversation?

- Hey Sal, first of all, nice video. The problem is, we're not given this much time while solving the questions in the exam. Any tips on how to solve such questions in a quicker span of time? Thank you :)(7 votes)
- Three tips on that: practice, practice and practice.(15 votes)

- What does the argument of z mean? I probably missed it somewhere.(10 votes)
- z means any complex number of the convex combination of z1 and z2(1 vote)

- The question was MCQ. How can there be more than one possible answer?(1 vote)
- in your IIT JEE exam you also get MCQ's with more than one option right

they are just given to confuse students and you are supposed to mark all the right answers...(4 votes)

- what is demoiveres theorem(0 votes)
- demoiveres theorem states that for any complex number (and, in particular, for any real number) x and integer n it holds that (cos x + i sin x)^n = cos(nx) + i*sin(nx), where i=sqrt(-1).(9 votes)

- i really love all the videos ...but hello there!... this is epic IIT JEE exam , in real exam you do not have this much time to solve question in depth. if only u can solve this question in few seconds ?(3 votes)
- well if u want to take this exam the best way to solve this type of questions is to keep practicing(0 votes)

- at6:37the absolute value of 1-t... wouldn't that be 1+t because it's the absolute value of it. I know it is ultimately positive, but there is a minus sign?(1 vote)
- absolute function is defined as follows:

IxI= +x when x>0

IxI= -x when x<0

here as 0<t<1, 1-t will be positive, so modulus of 1-t will be +(1-t)= 1-t

modulus does not simply mean changing negative to positive, abs(1-t) will give + or - sign to the whole term and not just 't'. had (1-t) been negative, absolute value would have been -(1-t)= -1+t..remember this!(4 votes)

- Hello, i was wondering what magnitude means? Is there a video that I might have skipped? Thanks :)(0 votes)
- magnitude is just the absolute value of a number

if you have a -3 then the magnitude of this quantity is 3

here you are just ignoring the direction....(2 votes)

- Why is D incorrect?(1 vote)
- D isn't incorrect. In the next video Sal explains why choice B is incorrect, but then (from about5:04) goes on to use that same reasoning to show that choice D is correct.(2 votes)

- Im following the Algebra (all content) series and have not skipped any lesson. Yet, i don't understand how z,z1,z2, and w are related and why sal is doing what he is doing in the video.

Is there any video I could watch for this to make some sense to me?(1 vote) - Sir What will be the ans

Q. If z = x - iy & z^1/3 = p + iq , then (x/p + y/q) / (p^2 + q^2) = ?(1 vote)

## Video transcript

Let z1 and z2 be two
distinct complex numbers. And let z equal,
and they say it's "1 minus t times z1 plus t times
z2, for some real number with t being between 0 and 1." And they say, "If the argument
w denotes the principal argument of a nonzero complex
number w, then?" And we know the argument is the
angle of kind of the position vector specifying the complex
number of the complex plane, and the real axis. Let me just draw that. So if we do an Argand diagram,
this is the imaginary axis. And this is the real axis. If this is our complex
number, if that is z, it's argument--
the argument of z-- is going to be this
angle right over here. So phi is equal to
the argument of z. That's all they're telling
us in this second part. Now, let's go through each of
these and see are they true. And just to be
clear, this is one of those problems where more
than one of these choices might be correct. So let's see if they're true. So let's first figure out what
the magnitude of z minus z1 is. So the magnitude
of z minus z1 is going to be the magnitude of--
so let me write-- this is going to be the magnitude of--
let's do the z part first. Let me write in the same colors. So if I would just
focus on the z first, z is this thing up here. And let me distribute the z1. So it's z1 minus tz1 minus
tz1, and then plus tz2. And from that, we
want to subtract z1. So from that, we want to
subtract z1, so minus Z1. And that and that cancel out. And let's see. We can factor out a t over here. So this is going to be equal to
the magnitude of-- let's factor out a t times z2 minus z1. So that is the
magnitude of z minus z1, this first term over here. Let's figure out the
magnitude of z minus z2. I'm going to color
code it. z minus z2 is equal to the
magnitude-- well, z is just this thing up here. Let me just write it out. So it is 1 minus t times z1
plus t times z2, that's z. And from that, we want to
subtract z2, so minus z2. So what can we do over here? We can take a t minus
1 out from here. We can factor out the z2
out of these two terms. So this is going to be
equal to the magnitude of 1 minus t times z1,
1 minus t times z1. That's this term
right over here. Plus-- let me do it in another
color-- plus t minus 1, times z2. The magnitude of this part over
here is this thing over there. Now, let's see what
happens when we add this thing to this thing. That's what choice A is doing. We're adding this
thing to this thing. Let's see if we can simplify it. So this becomes the absolute
value, or the magnitude, of t times z2 minus z1 plus--
I'll do the whole thing here in magenta-- plus
this thing over here. And this thing over here--
actually, before I even write it out-- how
can we simplify that? We'll have a 1 minus
t and a t minus 1. Well, I'll just
write it out here. But I'm going to change
it up a little bit. So this is equal
to the magnitude of 1 minus t times z1. And so that I have
a 1 minus t here, I'm just going to put
a negative out front. So minus 1, minus t,
I just swapped them. Negative 1 minus t is the
same thing as positive t minus 1, z2. And then this thing over here,
since I have the 1 minus t out there, this
becomes the magnitude of, I'm just factoring
out the 1 minus t, 1 minus t times z1 minus z2. So we have this thing. Let me copy and paste it. So, copy and paste. We have this thing
plus this thing. This is what this expression
A has simplified to. Now let's see if we can
simplify that even more. Let's see if we can
simplify it even more. So t is just a scalar. And t is between 0 and 1. They have told us that over
here, t is between 0 and 1. So this is positive. This right here is
a positive value. And then this right here is also
going to be a positive value. t is greater than 0,
and it is less than 1. So this is also going
to be a positive value. And these are just scalars. So this is going to
be the same thing. These are just
scaling the magnitude. So this is going to
be the same thing. These are positive values. So this is going to be t times
the absolute value-- actually let me not skip a step. This is going to be the same
thing as the absolute value of t times the absolute
value of z2 minus z1-- because this is
just scaling it-- plus the absolute
value of 1 minus t, times the absolute
value of z1 minus z2. Now let me be clear, the
absolute value of z1 minus z2 is going to be equal to the
absolute value of z2 minus z1. These vectors are just pointing
in different directions, or these complex numbers. One is just the
negative of the other. But their absolute values,
or their magnitudes, are going to be the same. So let me write z2 minus z1, the
absolute value of z2 minus z1, there. And the reason why
I'm doing it is so I get the same thing here. And I can factor it out. So the absolute
value of z1 minus z1 is the same thing as
the absolute value of z1 minus z2,
because it's just going in the other direction. Now, what can we do here? Well, the absolute
value of t, remember t is positive, so this is
just going to be equal to t. The absolute value of 1
minus t, once again, that's positive, so that's just
going to be 1 minus t. So we can factor
this business out. So we're going to
get t plus 1 minus t, times the absolute
value of z2 minus z1. Now, the t's cancel out here. We just got a one out front. So this is just equal to the
absolute value of z2 minus z1. So we see that
choice A does work. This plus this does
indeed equal that. I'm going to leave you there. And in the next
video, we're going to try out some of these
other possibilities to see if they
might also be true.