Algebra (all content)
- Intro to absolute value equations and graphs
- Worked example: absolute value equation with two solutions
- Worked example: absolute value equations with one solution
- Worked example: absolute value equations with no solution
- Solve absolute value equations
Worked example: absolute value equations with no solution
Solving the equation 4|x+10|+4 = 6|x+10|+10 to find that it has no possible solution. Created by Sal Khan.
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- Just out of curiosity, is there something similar to imaginary number i and square root, what makes absolute value of something to equal to a negative number?(13 votes)
- I would think not, since the absolute value function is specifically designed to ensure a positive output. Square roots only have positive outputs as a side effect of the squaring laws, so I would think i is a unique case compared to absolute value.(6 votes)
- I have a question, how would I solve a question like
| x - 1 | + |2 - x| = 14
Is it possible to solve this equation algebraically or do I solve this graphically.
- The proper way of doing the problem is to consider the points at which each of the terms whose absolute value is taken changes sign
So, equate each term to 0, e.g in this question x-1=0 implies the abs x-1 term changes sign at 1 and equating 2-x=0, implies it changes sign at 2
These two points divide the number line into 3 areas: x<1; 1<x<2 and x>2
also note that the x-1 term is positive for x>1 and negative for x<1
the reverse is true for 2-x, which is positive for x<2 and is negative for x>2
for the three areas formulate the equations keeping in mind the sign of the terms and you'll be good to go.
e.g for x<1; -(x-1)+(2-x)=14
for 1<x<2: (x-1)+(2-x)= 14
for x>2: (x-1)+(-(2-x)) = 14
Solve each of the three equations and find the value of x valid in each region. Hope , it helps.(7 votes)
- What if the absolute value is not same on both sides?
example: 2|x - 8| + 6 = 3|x + 9| - 8
Can I solve it?(3 votes)
- Does the absolute value equation have to be |x+a| = 0 to get the solution?(2 votes)
- If you have: |x+a|=0, you get one solution.
If you have: |x+a|=a positive number, you usually get 2 solutions.
If you have: |x+a|=a negative number, then it has no solution.
Hope this helps.(3 votes)
- ok, here's a problem I got wrong in the practice
Subtract 2|x+4| from both sides:
Subtract 8 from both sides:
Divide both sides by 3:
The absolute value cannot be negative. Therefore, there is no solution.
Because it always says when you take the absolute symbols off, you get a negative number as well as a positive number the solutions I came up with were
-3 and -5.
All throughout the practice there are solutions with fractions where both fractions are negative.
What's the difference? Why is this one unsolvable where problems with 2 negative fractions for answers are considered solvable?(3 votes)
- 2 negative fractions make up a positive number, just think about the x-(-a)= x+a(0 votes)
- So if the absolute value equals a positive number you can change it to a negative number to get an alternative answer, but if it's negative you can't change it to a positive?(1 vote)
- Absolute value is distance from 0. You can' that've a negative distance, so we put "no solution".(3 votes)
- Why do they have no solution?(1 vote)
- Say I have a number 't', which can take ANY real value, so it can be anything from -32222940 or 5.204. The |t| will ALWAYS be a positive number, right?
So now if I ask you to solve this equation:
|t| = -9, you would be very confused, because the |t| has to be a positive number, and the equation is telling you that there is a value t can take which would make |t| = -9. In truth, there is no number for which |t| can equal a negative number, and so it has no solution.
Sal's example is just slightly more complicated than this, but you'll see he used the same reasoning(3 votes)
- I am so confused for this equation. I have 3|x+1|+7=6|x+1|+6.
I watched all the videos but I am still very confused. Can anyone help?(1 vote)
- 1) Notice that the absolute values on both sides match. This means they can be combined just like 3y and 6y can be combined. So, start by subtracting 3|x+1| from both sides:
3|x+1|-3|x+1|+7 = 6|x+1|+6-3|x+1|
7 = 3|x+1|+6
2) Subtract 6 from both sides
7-6 = 3|x+1|+6-6
1 = 3|x+1|
3) Split the equation into 2:
1 = 3(x+1) and 1 = -3(x+1)
4) Solve each equation to get the solutions.
Hope this helps.(3 votes)
- So when you solve an absolute value equation, and you first get a negative it's no solution ,but if you solve it and you get a positive solution you can solve for two solutions making the other negative?
- Hi! :) Absolute value is simply the distance that number is from zero (0). Think of each number as a certain number of "jumps" from zero. Because it is a distance from zero, you can never have the answer of an absolute value equation equal to a negative number. For example, |5| = 5, |-6| = 6....... Hope this helps! :-)(2 votes)
- Do you always have to subtract something from the right-hand side or does it also work if you do it on the left hand side?(1 vote)
- You can do opposites from either side of the equation, so yes it works from both sides. You can also flip equations around from one side to the other.(2 votes)
So we're asked to solve for x, and we have this equation with absolute values in it. So it's 4 times the absolute value of x plus 10 plus 4 is equal to 6 times the absolute value of x plus 10 plus 10. And at first, this looks really daunting, but the key is to just solve for this absolute value expression and then go from there. Let me just rewrite it so that the absolute value expression really jumps out. So this is 4 times the absolute value of x plus 10 plus 4 is equal to 6 times the absolute value of x plus 10 plus 10. So let's get all of the absolute values of x plus 10 on the left-hand side. So I want to get rid of the 6 times the absolute value of x plus 10 on the right. Well, how would I do that? Well, I could subtract 6 times the absolute value of x plus 10 from the right, but we've already seen this multiple times. If these two things are equal, and if I want to keep them equal, if I subtract 6 from the right-hand side, I've got to subtract-- or if I subtract 6 times the absolute value of x plus 10 from the right-hand side, I have to subtract the same thing from the left-hand side. So we're going to have minus 6 times the absolute value of x plus 10. And likewise, I want to get all my constant terms, I want to get this 4 out of the left-hand side. So let me subtract 4 from the left, and then I have to also do it on the right, otherwise my equality wouldn't hold. And now let's see what we end up with. So on the left-hand side, the 4 minus 4, that's 0. You have 4 of something minus 6 of something, that means you're going to end up with negative 2 of that something. Negative 2 of the absolute value of x plus 10. Remember, this might seem a little confusing, but remember, if you had 4 apples and you subtract 6 apples, you now have negative 2 apples, I guess you owe someone the apples. Same way, you have 4 of this expression, you take away 6 of this expression, you now have negative 2 of this expression. Let me write it a little bit neater. So it's negative 2 times the absolute value of x plus 10 is equal to, well the whole point of this, of the 6 times the absolute value of x plus 10 minus 6 times the absolute value of x plus 10 is to make those cancel out, and then you have 10 minus 4, which is equal to 6. Now, we want to solve for the absolute value of x plus 10. So let's get rid of this negative 2, and we can do that by dividing both sides by negative 2. You might realize, everything we've done so far is just treating this red expression as almost just like a variable, and we're going to solve for that red expression and then take it from there. So negative 2 divided by negative 2 is 1. 6 divided by negative 2 is negative 3. So we get the absolute value of x plus 10 is equal to negative 3. Now, this gets us to a very interesting situation. You might say maybe this could be the positive version or the negative, but remember, absolute value is always non-negative. If you took the absolute value of 0, you would get 0. But the absolute value of anything else is going to be positive. So this thing right over here is definitely going to be greater than or equal to 0. Doesn't matter what x you put in there, when you take its absolute value, you're going to get a value that's greater than or equal to 0. So there's no x that you could find that's somehow-- you put it there, you add 10, you take the absolute value of it, you're actually getting a negative value. So this right over here has absolutely no solution. And I'll put some exclamation marks there for emphasis.