- Systems of equations: trolls, tolls (1 of 2)
- Systems of equations: trolls, tolls (2 of 2)
- Testing a solution to a system of equations
- Systems of equations with graphing: y=7/5x-5 & y=3/5x-1
- Systems of equations with graphing: exact & approximate solutions
- Systems of equations with graphing
Sal graphs the following system of equations and solves it by looking for the intersection point: y=7/5x-5 and y=3/5x-1. Created by Sal Khan.
Want to join the conversation?
- What do you mean when you say "when x is equal zero, y is equal to negative 5," That did not make sense to me. i could be because of the way I explain things when i grph but it did not make sense to me.(37 votes)
- He meant that the y-intercept of that equation is -5. At the y-intercept, x=0 and y=-5 for this equation.(12 votes)
- I'm sooo confused.
How exactly do you plot it?(24 votes)
- you take the y intercept and plot it on the y-axis then use the slope (example:4x or 2/3x) if its 4 then go four up and if its -4 go four down if its a fraction like 3/5 then use rise over run and go up 3 and over 5(2 votes)
Why do we learn this?
So when we encounter trolls, and they want us to figure out what types of money they have in their pockets, we don't die.(18 votes)
- i thought you move 3 to the right and 5 up for the equation's rise over run(10 votes)
- Yes, the slope means rise over run. It doesn't make sense for Rise to mean go right. Think of the meaning of the word. Rise means go up. So, Rise = up/down and Run = left/right.
Hope this helps.(17 votes)
- what if it is just a whole number, not a fraction(10 votes)
- So, how would you plot something like
I cannot figure out how to plot it.(4 votes)
- I got lost instantly.(8 votes)
- What we're doing here is graphing out a line based on this equation. First we can find the y-intercept (the point where the line crosses the x axis). Since the y axis is naturally at x = 0, we can plug x into the equation and then solve for y. In the first equation in this video, that would be y=0-5. Now that very obviously means that one point on this line is 0,5. Then, since we know the slope is 7/5 (y=mx+b, remember?) we can find another point by "rising" 7 and "running" 5. That means we get another point we can use to graph the line, in this case 5,12. Then, you do the exact same thing to graph the second line and the intersection is the solution to this problem. I know this is late but I hope it helps anyone who is struggling.(1 vote)
- What is the troll he's talking about in0:02?(4 votes)
- I sometimes still have a hard time finding the slope. On :36 it says the Y intercept is equal to 5. Does that mean that the -5 is the Y intercept. If so than the number without the variable is always the Y intercept?(4 votes)
- the y intercept is -5 is correct. Since it is where x = 0, no matter what the slope is, if I multiply by 0 I will always get zero.(3 votes)
- I'm really confused how he did it because all i saw him do was move around the dots. Can someone please help me?(1 vote)
- Yeah, that's pretty much it for this exercise: moving around dots, but the "math" part is the line that's connected to the dots. You're basically "drawing" a line by moving the dots. I'll see if I can explain it a different way to make it easier to understand.
y = x
This one's pretty simple to graph. It's just a diagonal line where at any point it's the same distance from the x axis as it is from the y axis. (I really wish I could show you graphs in these answers but I don't think I can. Sadness) All the other equations we'll talk about will look like this one, but changed a little bit.
Let's try another.
y = x + 1
This is just like the other one, but it's shifted up one unit. If x = 1, then y = 1 + 1 or 2. If x = 7 then y = 7 + 1 which is 8.
y = x + 4
This one's the same as the other one, but shifted up 4 units.
Now let's change the slope of the line.
y = 2x
Now the line is steeper. If x = 1 then y = 1*2 or 2 If x = 5 then y = 5*2 or 10
y = ½x
This one's like the other one, except instead of the line being steeper, it's less steep. Instead of multiplying by 2, we divide by 2. If x = 1 then y = 1/2. If x = 8 then y = 8/2 which equals 4
Okay, let's do one last one.
y = 3x + 2
In this one, we have to shift it up, and make it steeper. If x = 1 then y = 1*3 + 2 which equals 5. If x = 7 then y = 7*3 +2 which is (seven times three is 21, plus 2...) 23
I don't know if this was helpful at all but this concept is really hard to explain without being able to draw. Please let me know if this helped, or if you have any further questions. :)(9 votes)
Just in case we encounter any more trolls who want us to figure out what types of money they have in their pockets, we have devised an exercise for you to practice with. And this is to solve systems of equations visually. So they say right over here, graph this system of equations and solve. And they give us two equations. This first one in blue, y is equal to 7/5x minus 5, and then this one in green, y is equal to 3/5x minus 1. So let's graph each of these, and we'll do it in the corresponding color. So first let's graph this first equation. So the first thing I see is its y-intercept is negative 5. Or another way to think about it, when x is equal to 0, y is going to be negative 5. So let's try this out. So when x is equal to 0, y is going to be equal to negative 5. So that makes sense. And then we see its slope is 7/5. This was conveniently placed in slope-intercept form for us. So it's rise over run. So for every time it moves 5 to the right it's, going to move seven up. So if it moves 1, 2, 3, 4, 5 to the right, it's going to move 7 up. 1, 2, 3, 4, 5, 6, 7. So it'll get right over there. Another way you could have done it is you could have just tested out some values. You could have said, oh, when x is equal to 0, y is equal to negative 5. When x is equal to 5, 7/5 times 5 is 7 minus 5 is 2. So I think we've properly graphed this top one. Let's try this bottom one right over here. So we have when x is equal to 0, y is equal to negative 1. So when x is equal to 0, y is equal to negative 1. And the slope is 3/5. So if we move over 5 to the right, we will move up 3. So we will go right over there, and it looks like they intersect right at that point, right at the point x is equal to 5, y is equal to 2. So we'll type in x is equal to 5, y is equal to 2. And you could even verify by substituting those values into both equations, to show that it does satisfy both constraints. So let's check our answer. And it worked.