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## Algebra I (2018 edition)

### Course: Algebra I (2018 edition) > Unit 10

Lesson 3: Modeling with linear inequalities- Writing two-variable inequalities word problem
- Solving two-variable inequalities word problem
- Graphs of two-variable inequalities word problem
- Two-variable inequalities word problems
- Interpreting two-variable inequalities word problem
- Modeling with systems of inequalities
- Writing systems of inequalities word problem
- Solving systems of inequalities word problem
- Graphs of systems of inequalities word problem
- Systems of inequalities word problems
- Analyzing structure with linear inequalities: fruits
- Analyzing structure with linear inequalities: balls
- Analyzing structure with linear inequalities

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# Graphs of systems of inequalities word problem

Given the graph of a two-variable linear inequality that models a context about chopping vegetables, Sal finds if there's enough time to chop!

## Want to join the conversation?

- At0:04it is said carrots and broccoli take the same time to get cut but graph of inequality doesn't show it. It says 15 broccoli and 0 carrots can be cut in 540 seconds at the same time shows 30 carrots and 0 broccoli can be cut in 540 seconds.

Does this mean,

15 B + 0 C = 540 s

30 C + 0 B = 540 s

B= 36 s

C= 18 s

??

This contradicts the fact in the question(1 vote)- It actually says that it takes the same number of seconds to chop each carrot and the same number of seconds to chop each broccoli. This does not mean that the carrots and broccoli are chopped at the same rate, but that the rate of chopping carrots is constant (as you found 18 sec/carrot) and the rate of chopping broccoli is constant (36 sec/carrot).(13 votes)

- Does this mean that carrots are cut at a rate of 540/30 and broccoli heads are cut at a rate of 540/15?(8 votes)
- Yes, although it probably wouldn't be literal in real life.(0 votes)

- Q: How do you know which variable to assign to which axes.

I saw that the y axes was replaced by B and the x axes by C.

Why not have C be the y axes and B be the x axes?(3 votes)- They both work! The nice thing about algebra is that you can make the axes whatever you want. Sometimes there are conventions (time is the x axis), but it doesn't matter which you use.(5 votes)

*Can someone plz help me on how the answer is 20?*At1:48, Why does Sal shade the overlap?(1 vote)- sal shades the overlap due to the property of inequalitites. when inequalitites are graphed and multiple inequalities are graphed, to find answers that satisfy all of the inequaitites you will need to shade in a particular part of the graph. to help remember how to graph these inequalities, remember:

< is a dashed line and shading below

> is a dashed line and shading above

≤ is a solid line and shading below

≥ is a solid line and shading above(5 votes)

- Could we have calculated equation B from the information given, or not? I noticed that it was given a y-int of 15 and x-int of 30 - this must have been using additional information? If not, I would appreciate any advice on how it could be calculated from the info given. Thanks.(1 vote)
- I didn't understand inequality B and, how the line was graphed?(1 vote)
- Arbaaz,

The point of this video is to discuss how to understand the graphed solution. There isn't really enough information written to determine how the line was graphed. We would need the number of seconds it takes to chop each type of vegetable to walk through graphing the line.(1 vote)

- Will it always be the intersection point?(1 vote)
- Anoosha,

No, there will not always be an intersection point. There are times when the lines will be parallel, which makes the answer the empty set.(1 vote)

- Why is it shaded blue if it says she wants to chop at least 20 vegetales? Should it not be below?(0 votes)
- Isaiah,

Think of it this way:

She wants to chop**at least**20 vegetables -**NOT less than**20 vegetables.

She wants to chop 20 vegetables or**more**.

Vegetables she wants to chop >= 20.(3 votes)

- The highest no. of carrots she can chop in the given, is it 30?(0 votes)
- I would believe so(1 vote)

- Wait so let me get this straight. The total number of vegetable has to be AT LEAST the constraint of 20, but she cannot cut anymore than this number multiplied by the given time it takes to cut each vegetable?(0 votes)
- She wants to cut at least 20 so she can cut as much as 30 within her time limit(1 vote)

## Video transcript

- [Voiceover] "Ksenia
wants to chop broccoli "and carrots for a competition. "It takes her the same number of seconds "to chop each carrot, and
it takes her the same number "of seconds to chop each broccoli head. "Her goal is to chop
at least 20 vegetables "with a time limit of
540 seconds," all right. "The graph below represents the set "of all combinations of
carrots and broccoli. "Inequality A," let's see,
"Inequality A represents "the range of all combinations
Ksenia wants to chop." Because she wants to chop
at least 20 vegetables. So, that's what Inequality
A is representing, that she wants to chop
at least 20 vegetables. So, all this blue shaded
area and even the line, is a solid line so it
includes point on the line. These are all of the scenarios where she's chopping
at least 20 vegetables, all this blue area
including the blue line. And it says, "Inequality
B represents the range of all combinations she can
chop with her time limit." So, Inequality B, this is
all of the combinations where she is within her time limit, where she is not spending
any more than 540 seconds. "What is the least number of carrots Ksenia can chop while achieving her goal?" Well, her goal, remember she wants to chop at least 20 vegetables. So, you want to be in the blue area. You want to be in the solution set for Inequality A, which
would be the blue area or on the blue line. And she wants to achieve her goal of meeting the time limit. So, she needs to also
be in the solution set for Inequality B so she also has to be in the green area or on the green line. And so the overlap of the two, if she's meeting both constraints, it's going to be all of this area. This is the overlap of the two solution sets. So, in this overlap where is
the least number of carrots. "What is the least
number of carrots Ksenia can chop while achieving her goal." So, if we see here, the
least number of carrots, you might tempted to
say, "Okay, 20 carrots, that is in the solution set." That would be 20 carrots
and zero broccoli heads but you can actually find a combination that has even fewer carrots. You can go all the way to this point because remember the points on the lines are also included in the solution sets, because they are solid
lines not dash lines. So, this point right over here, 10 carrots and 10 broccoli heads actually meets her goal. So, let me write that down. 10 carrots and 10 broccoli, 10 broccoli heads. Let me just write that, 10 broccoli heads. So, that's the least amount. If you wanted to somehow figure out less than 10 carrots, in
any of those scenarios there's no overlap. You know, if you say,
"Oh, is there any way "to do nine carrots?" If you look over here there's no overlap at c equals nine between
the two solution sets. So, the minimum right over here is actually the point of intersection of these two lines. 10 carrots, 10 broccoli heads that's the combination
that has her chopping the minimum number of carrots while achieving, frankly, her goals, both of her goals. Being under time and chopping
at least 20 vegetables.