8th grade (Eureka Math/EngageNY)
- x-intercept of a line
- Intercepts from a table
- Intercepts from a graph
- Intercepts from an equation
- Worked example: intercepts from an equation
- Intercepts from an equation
- Slope & direction of a line
- Intro to slope
- Slope formula
- Worked example: slope from graph
- Slope of a line: negative slope
- Slope from graph
- Worked example: slope from two points
- Slope of a horizontal line
- Slope from two points
- Intro to slope-intercept form
- Slope-intercept intro
- Slope from equation
- Graph from slope-intercept equation
- Graph from slope-intercept form
- Slope-intercept equation from graph
- Slope-intercept equation from graph
- Slope-intercept equation from slope & point
- Slope-intercept equation from two points
- Slope-intercept from two points
- Slope-intercept form from a table
- Converting to slope-intercept form
- Slope-intercept form problems
- Proving slope is constant using similarity
- Intro to point-slope form
Learn to convert equations like 4x + 2y = -8 into slope-intercept form. Created by Sal Khan and Monterey Institute for Technology and Education.
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- On line A why did he divide all terms by 2?(27 votes)
- In order to eliminate the coefficient (2) on Y. If the coefficient were left attached to that Y right there, then we would not have a value for Y by itself, which is what the slope-intercept equation requires.
This video might help: http://www.khanacademy.org/video/simple-equations?playlist=Algebra
I hope that's helpful!(25 votes)
- why did he subtract 4? shouldnt he divide by 4?(12 votes)
- Could anybody please tell me how you graph a fractional number, like y=5/8x+8/9(5 votes)
y=5/8x+8/9 is a linear equation. So you just want to find any two points. plot the two points, and draw a line through the two point you plotted.
If you choose 0 for x then y=5/8 * 0 + 8/9 = 8/9 so your first point is (0,8/9)
If you choose 8 for x then y = 5/8 * 8 + 8/9 = 5 + 8/9 = 5 8/9
so another point is (8,5 8/9).
So plot the point (0,8/9) which is just below of (0,1) and
plot the point (8, 5 8/9) which is just below of (5,6)
and then draw a line through the two points.
The other method you can use is to plot the y-intercept.
The equation y=5/8x+8/9 is is slope y-intercept form
so the y intercept is at (0,8/9). Plot that point.
The slope is 5/8, so from your y-intercept point, count right 8 and then go up 5. And remember it is just below the line as you count going up.
The graph should look something like this: https://www.khanacademy.org/cs/y58x-89/5900563254345728
I hope that helps make it click for you.(13 votes)
- At time3:30you said that you can't make it into slope interval form. Then you made a line at -2x. Why where you able to do that. Also what is the x mean in "y=mx+b".(6 votes)
- In y=mx+b must b be a whole number(3 votes)
- No, b does not have to be a whole number. b is simply where the line will cross the y-axis when this line is graphed. So, if b=1/2 then the line will cross the y axis between the 0 and the 1.(11 votes)
- What's linear?(5 votes)
- How did he get (0,-4) from y= -2x- 4?(4 votes)
- At2:14how did Sal instantly know the slope of the line?
Also, if y= mx +b, shouldn't the slope in y = -2x - 4 be -2? the slope is m, and in the first equation is being multiplied by the x, so without the x the slope in the second equation would be -2?(3 votes)
- how do i find the slope intercept form if the equation is written differently?(2 votes)
- Are there any possibility that a linear equation can't convert into slope intercept form?(2 votes)
- Good question!
In the coordinate plane, the only type of line with an equation that can't be converted into y = mx + b form (slope-intercept form) is a line with an equation equivalent to the form x = c, where c is a constant.
This exceptional type of line is a vertical line with undefined slope. The graph has no y-intercepts if c is nonzero, and all real numbers for its y-intercepts if c is zero.
Have a blessed, wonderful day!(2 votes)
We're asked to convert these linear equations into slope-intercept form and then graph them on a single coordinate plane. We have our coordinate plane over here. And just as a bit of a review, slope-intercept form is a form y is equal to mx plus b, where m is the slope and b is the intercept. That's why it's called slope-intercept form. So we just have to algebraically manipulate these equations into this form. So let's start with line A, so start with a line A. So line A, it's in standard form right now, it's 4x plus 2y is equal to negative 8. The first thing I'd like to do is get rid of this 4x from the left-hand side, and the best way to do that is to subtract 4x from both sides of this equation. So let me subtract 4x from both sides. The left hand side of the equation, these two 4x's cancel out, and I'm just left with 2y is equal to. And on the right-hand side I have negative 4x minus is 8, or negative 8 minus 4, however you want to do it. Now we're almost at slope-intercept form. We just have to get rid of this 2, and the best way to do that that I can think of is divide both sides of this equation by 2. So let's divide both sides by 2. So we divide the left-hand side by 2 and then divide the right-hand side by 2. You have to divide every term by 2. And then we are left with y is equal to negative 4 divided by 2 is negative 2x. Negative 8 divided by 2 is negative 4, negative 2x minus 4. So this is line A, let me graph it right now. So line A, its y-intercept is negative 4. So the point 0, negative 4 on this graph. If x is equal to 0, y is going to be equal to negative 4, you can just substitute that in the graph. So 0, 1, 2, 3, 4. That's the point 0, negative 4. That's the y-intercept for line A. And then the slope is negative 2x. So that means that if I change x by positive 1 that y goes down by negative 2. So let's do that. So if I go over one in the positive direction, I have to go down 2, that's what a negative slope's going to do, negative 2 slope. If I go over 2, I'm going to have to go down 4. If I go back negative 1, so if I go in the x direction negative 1, that means in the y direction I go positive two, because two divided by negative one is still negative two, so I go over here. If I go back 2, I'm going to go up 4. Let me just do that. Back 2 and then up 4. So this line is going to look like this. Do my best to draw it, that's a decent job. That is line A right there. All right, let's do line B. So line B, they say 4x is equal to negative 8, and you might be saying hey, how do I get that into slope-intercept form, I don't see a y. And the answer is you won't be able to because you this can't be put into slope-intercept form, but we can simplify it. So let's divide both sides of this equation by 4. So you divide both sides of this equation by 4. And you get x is equal to negative 2. So this just means, I don't care what your y is, x is just always going to be equal to negative 2. So x is equal to negative 2 is right there, negative 1, negative 2, and x is just always going to be equal to negative 2 in both directions. And this is the x-axis, that's the y-axis, I forgot to label them. Now let's do this last character, 2y is equal to negative eight. So line C, we have 2y is equal to negative 8. We can divide both sides of this equation by 2, and we get y is equal to negative 4. So you might say hey, Sal, that doesn't look like this form, slope-intercept form, but it is. It's just that the slope is 0. We can rewrite this as y is equal to 0x minus 4, where the y-intercept is negative 4 and the slope is 0. So if you move an arbitrary amount in the x direction, the y is not going to change, it's just going to stay at negative 4. Let me do a little bit neater. y is just going to stay at negative 4. Or you can just interpret it as y is equal to negative 4 no matter what x is. So then we are done.