Can't we move the whole line instead of moving the points to find out if the slope is the same between the point and it's image?

You can, it is just easier for some people to understand moving the points instead of moving the whole line. However, I do prefer moving the line and if you find it easier, I wholly recommend doing it how you feel comfortable.

My question is, how am I suppose to perform reflections on pieces of paper, without the reflect tool that Khan Academy provides? Really confused, test coming up, help!

you count from the x/y axis line to your position/dot. then, you go to the the other side of the x/y axis and count the same number of spaces towards the opposite direction. hope you ace your test!

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Course: Geometry (all content) > Unit 10

Lesson 9: Old transformations videos

Performing reflections: rectangle (old)

Name: Performing reflections: rectangle (old)
Uploaded: 2013-12-24T23:36:04Z
Description: An older video where Sal uses the interactive widget to find the image of a rectangle under a reflection.

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An older video where Sal uses the interactive widget to find the image of a rectangle under a reflection. Created by Sal Khan.

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Wrath Of Academy
Posted 10 years ago. Direct link to Wrath Of Academy's post “So the slope of a line ne...”
So the slope of a line never changes if it is reflected across a line of the same slope?
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(22 votes)
Answer
- Tanmay
  Posted 9 years ago. Direct link to Tanmay's post “But if it is reflected ac...”
  But if it is reflected across a line that has a slope of 0 or opposite. Then the slope may change to being a positive or negative.
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  (1 vote)
Karlar
Posted 10 years ago. Direct link to Karlar's post “Does programming involve ...”
Does programming involve some math?
Button navigates to signup pageComment on Karlar's post “Does programming involve ...”
(5 votes)
Answer
- AraPJ
  Posted 8 years ago. Direct link to AraPJ's post “Everything in the real wo...”
  Everything in the real world includes math including the room you are sitting in now
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  (1 vote)
John Lee
Posted 10 years ago. Direct link to John Lee's post “Can't we move the whole l...”
Can't we move the whole line instead of moving the points to find out if the slope is the same between the point and it's image?
Button navigates to signup pageComment on John Lee's post “Can't we move the whole l...”
(4 votes)
Answer
- Tasnim Thakur
  Posted 10 years ago. Direct link to Tasnim Thakur's post “You can, it is just easie...”
  You can, it is just easier for some people to understand moving the points instead of moving the whole line. However, I do prefer moving the line and if you find it easier, I wholly recommend doing it how you feel comfortable.
  Comment on Tasnim Thakur's post “You can, it is just easie...”
  (4 votes)
Velvel Marasow
Posted 10 years ago. Direct link to Velvel Marasow's post “Why is the y intercept at...”
Why is the y intercept at zero? just wondering.
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(3 votes)
Answer
brewbooks
Posted 9 years ago. Direct link to brewbooks's post “Can a reflection always b...”
Can a reflection always be used in place of a rotation and translation?
I noticed while working the problems that I could usually come up with a reflection (one step that solved the problem instead of using a rotation and translation (two steps) and I am wondering if that is generally true?
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(3 votes)
Answer
- Taamer7356
  Posted 8 years ago. Direct link to Taamer7356's post “yah i agree on your sayin...”
  yah i agree on your saying i think that reflection always is used in place of a rotation.
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  (1 vote)
Tanmay
Posted 9 years ago. Direct link to Tanmay's post “What does the equation me...”
What does the equation mean? How do you use it to find the slope for the reflection?
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(2 votes)
Answer
barbod.nikzad
Posted 8 years ago. Direct link to barbod.nikzad's post “My question is, how am I ...”
My question is, how am I suppose to perform reflections on pieces of paper, without the reflect tool that Khan Academy provides? Really confused, test coming up, help!
Button navigates to signup pageButton navigates to signup page
(2 votes)
Answer
- ANCANC
  Posted 8 years ago. Direct link to ANCANC's post “you count from the x/y ax...”
  you count from the x/y axis line to your position/dot. then, you go to the the other side of the x/y axis and count the same number of spaces towards the opposite direction.
  hope you ace your test!
  Comment on ANCANC's post “you count from the x/y ax...”
  (2 votes)
Christian Silva
Posted 8 years ago. Direct link to Christian Silva's post “What does it mean to say ...”
What does it mean to say a figure has rotational symmetry?
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(2 votes)
Answer
- Buffy Anne Summers
  Posted 8 years ago. Direct link to Buffy Anne Summers's post “If an object has rotation...”
  If an object has rotational symmetry, it means that if you rotate a part of it around, it will look the same as another part of the same object. Hmm, it's kinda hard to explain. Maybe this will help:
  
  https://upload.wikimedia.org/wikipedia/commons/thumb/3/36/The_armoured_triskelion_on_the_flag_of_the_Isle_of_Man.svg/330px-The_armoured_triskelion_on_the_flag_of_the_Isle_of_Man.svg.png
  
  So, the figure pasted above has rotational symmetry because if you rotate one 'leg' around far enough, it will be the exact same shape as another leg in the same image. Make sense?
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  (1 vote)
Teresa Smith Brazell
Posted 8 years ago. Direct link to Teresa Smith Brazell's post “what is the reflection of...”
what is the reflection of triangle (1,4) (3,-2) (4,2) over the x-axis?
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(1 vote)
Answer
Jan Bukhari
Posted 8 years ago. Direct link to Jan Bukhari's post “Fractions in coordinate p...”
Fractions in coordinate plane? I am Confused. 1/3x ?
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(2 votes)
Answer
- Wiz054
  Posted 8 years ago. Direct link to Wiz054's post “You may already know afte...”
  You may already know after 12 days but to be clear, a linear slope is always the (change in y) over (change in x)
  
  (y2-y1) / (x2-x1) where y2 and x2 is a coordinate (x2, y2) at any two points and y1 and x1 are different coordinates at any two points (x1,y2)
  (the 1 and 2 should be smaller numbers)
  this will give you the slope.
  
  The slope represent that any number that slope mulitplies with x will be y in a y=slope * x
  (usually the linear equations looks like y = kx + b where k is slope)
  
  for y = slope * x, the slope is -1/3 x, so if x = 3 then y = (-1*3)/3 = -1
  gives coordinate (3,-1)
  
  if x is = 9, then y = (-1*9)/3 = -3
  gives coordinate (9, -3)
  and
  you can see this is true when change in y/change in x = slope
  (-3-(-1))/(9-(3)) = (-2/6) = -1/3
  
  hope this made sense or helped.
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  (0 votes)

Video transcript

Perform a reflection over the line y is equal to negative 1/3 x. And then they want us to figure out what these different points map to on the reflection. And then they ask, is the slope of the segment between point A and its image is, and then blank, the slope of the segment between point B and its image. So let's just think about this step by step. So first, let's perform the reflection over the line y is equal to negative 1/3 x. So we want to reflect. So negative 1/3 x. So its y-intercept is 0. And it has a slope of negative 1/3, which means every time-- whoops, so let me put this right over here-- and that means every time we move positive 3 in the x direction, we move down once in the y direction. So this right over here, this is y is equal to negative 1/3 x. And so let's do our reflection. Whoops. To do the reflection, I've got to press this. So let's do our reflection. There we go. All right, this is exciting. So what does point A map to? Well, point A maps to this point right over there. And so that is the point negative 4, 8. And point B maps to this point, which is the point 8, positive 4. And then, they say the slope of the segment between point A and its image, so that's this segment between point A and its image. So actually let me take this reflection tool to just show you that line. So that's this segment right over here. The slope of the segment between point A and its image, that's this slope right over here, is blank the slope of the segment between point B and its image. Well, point B and its image, that line right over here, is going to have the same slope. And that makes sense, because they're both going to be perpendicular to what we were reflecting around. They're both going to be perpendicular to y is equal to negative 1/3 x. So they're going to have a negative reciprocal of negative 1/3 slope, which is positive 3. And you see this has a slope of positive 3, and that this right over here has a slope of positive 3. Every time you increase one in the x direction, you increase y by three units. So the slope is equal to. And we check our answer. And we got it right.